Are you trying to write a balanced reaction equation between water and sodium metal.
Here is the reaction equation
2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)
Sodium metal , together with other Group '1' metals (Alkali metals) is highly reactive with water and oxygen, so it is kept under oil, a hydrocarbon, no oxygen present.
In reacting with water it form the hydroxide and liberates hydrogen gas.
It is quite spectacular reaction. If you place a small (pin head sized) pellet in a water bath, it will spit , fizz, fume and race around the surface of the water. It will also occasionally 'pop' ; the liberated hydrogen igniting. .
Potassium and rubidium do exactly the same , but more violently.
The general equation is
2M(s) + 2H2O(l) = 2MOH(aq) + H2(g)
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
The balanced equation for the reaction between sodium and hydrogen gas to form sodium hydride is: 2 Na + H2 -> 2 NaH
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
Yes, the water and sodium produce sodium hydroxide and hydrogen!
The balanced equation for Na and H2so4 is Na+ H2SO4 = na2so4 + h2 it is self balanced The balanced equation for Na and H2so4 is Na+ H2SO4 = na2so4 + h2 it is self balanced ---- The answer above, H2SO4 is sulfuric acid. The formula for hydrochloricacid is HCl. Therefore: the equation is: Na + HCl --> NaCl + H2 The balanced equation would be (by my working): 2Na + 2HCl --> 2NaCl + H2 However, this is just how I would work it out and may again be wrong. Tryna help 8)
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
The reaction of Na (sodium) with H2O (water) produces NaOH (sodium hydroxide) and H2 (hydrogen gas). So, the equation would be 2Na + 2H2O → 2NaOH + H2.
Na + H2O --> NaOH + H2
2Na + 2H2O -> H2 + 2NaOH
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
The balanced equation for the reaction between sodium and hydrogen gas to form sodium hydride is: 2 Na + H2 -> 2 NaH
2Na + 2H2O -------> 2NaOH + H2
The chemical equation is 2Na + H2SO4 --> Na2SO4 + H2
It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
The balanced chemical equation for the reaction between Na and H2O to form NaOH and H2 is: 2Na + 2H2O → 2NaOH + H2. The equation is balanced as the same number of atoms of each element are present on both sides of the equation.
To determine how many grams of H2 can be produced from the reaction of sodium with water, we first use the balanced chemical equation: 2 Na + 2 H2O → 2 NaOH + H2. The molar mass of sodium (Na) is approximately 23 g/mol, so 72 g of sodium corresponds to about 3.13 moles of Na (72 g / 23 g/mol). According to the equation, 2 moles of Na produce 1 mole of H2, so 3.13 moles of Na will produce about 1.57 moles of H2. Since the molar mass of H2 is about 2 g/mol, this results in approximately 3.14 grams of H2 (1.57 moles × 2 g/mol).
None. There is no hydrogen in sodium