Fe3O4 can be considered to be 1:1 mixture of FeO and Fe2O3.
Oxidation number in FeO:
+2 for Fe and -2 of O
Oxidation number in Fe2O3:
+3 for Fe and -2 of O
Iron (Fe) can have oxidation numbers +2 and +3 in compounds.
No. it can't be fractional. However you can get fractional answers uch as Fe in Fe3O4 where the average oxidation state is 2.666.... You need to know something about the structure that will tell you what oxidation numbers of the Fe in this case two Fe with +3 and one Fe with +2 in each formula unit.
The oxidation number of Fe in Fe2S3 is +3. This is because the overall charge of the Fe2S3 compound is 0, and since there are 2 Fe atoms each with an unknown oxidation number "x" and 3 S atoms each with an oxidation number of -2, the sum of the oxidation numbers must equal 0. Solving for x gives +3 for the oxidation number of Fe.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
In Fe3O4, the oxidation number of Fe is +8/3. This can be found by setting up an equation where the total sum of the oxidation numbers in the compound equals the overall charge. In this case, Fe3O4 has a neutral charge, so the total sum of oxidation numbers is zero.
Oxidation numbers in Fe2O3 are respectively: Fe => +3 and O => -2
Iron (Fe) can have oxidation numbers +2 and +3 in compounds.
No. it can't be fractional. However you can get fractional answers uch as Fe in Fe3O4 where the average oxidation state is 2.666.... You need to know something about the structure that will tell you what oxidation numbers of the Fe in this case two Fe with +3 and one Fe with +2 in each formula unit.
The oxidation number of Fe in Fe2S3 is +3. This is because the overall charge of the Fe2S3 compound is 0, and since there are 2 Fe atoms each with an unknown oxidation number "x" and 3 S atoms each with an oxidation number of -2, the sum of the oxidation numbers must equal 0. Solving for x gives +3 for the oxidation number of Fe.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
In Fe3O4, the oxidation number of Fe is +8/3. This can be found by setting up an equation where the total sum of the oxidation numbers in the compound equals the overall charge. In this case, Fe3O4 has a neutral charge, so the total sum of oxidation numbers is zero.
In Fe2O3, iron (Fe) has an oxidation number of +3, while oxygen (O) has an oxidation number of -2. This means that each Fe atom contributes +3 to the compound, and each O atom contributes -2.
The oxidation number of carbon in Fe(CN)6^3- is -3. To find this, you can set up the equation where the total charge of the complex ion equals the sum of the oxidation numbers of each element in the ion and solve for the unknown oxidation number.
The oxidation number of Fe in Fe2S3 is +3. This can be determined by setting up an equation where the total oxidation number of the compound is equal to zero, and solving for the unknown oxidation number of Fe.
The oxidation number of Fe in FeBr2 is +2 because each Br has an oxidation number of -1 and the overall charge of the compound is zero.
The oxidation number of Fe in Fe3+ is +3. This is because Fe is a transition metal and can exhibit multiple oxidation states. In this case, Fe has lost three electrons to form a 3+ charge.
Transition elements usually have more than one oxidation number. In different oxidation numbers, the ions show different colors. Some of the ranges: Cu from +1 to +2; Cr from +2 to +6; Ni from +2 to +3; Co from +2 to +3 and Mn from +2 to +7.