Without stating units, it is impossible to answer this question accurately. However, the equation you would need is q=mc∆T, where q is the heat flow (the 53.0 listed, likely Joules), m is the mass of the unknown metal (11.1, likely grams), c is the specific heat of the metal (the unknown you need to solve for), and ∆T is the change in temperature of the metal (24.1-13.0, likely Celcius). Rearranged to solve for specific heat, the question is c=q/m∆T.
To answer this question, you need to know the heat capacity (C) for silver (Ag). It happens to be 0.240 J/g/deg. Then you can use the formula q = mC∆T where q = heat; m = mass; C = sp.heat cap; ∆T = change in temp. q = (252 g)(0.240 J/g/deg)(63.2 deg) = 3822 Joules
q = m x C x ΔT q = amount of heat energy gained or lost by substance = 1560 calories m = mass of sample in grams = 312g C = heat capacity (calorie/g oC) =? ΔT = change in temperature = 15 oC Solve for C C = q/mΔT = 1560cal/(312g)(15 oC) = 0.33cal/g oC
q = m x C x Δt, where q is amt of heat gained or lost, C is specific heat capacity, and Δt is change in temperature.Known:q = 2000Jm = 4gΔt = 5oCEquation:C = q/mΔtSolution:C = 2000J/4g5oC = 2000J/20goC = 100J/goC
Q = m*c*\delta t\, where Q = heat flow, m = mass, c = specific heat capacity, and \delta t\ = change in temperature. 88.2Cal = 13.4g*c*153 degrees C. Simple algebra yields c = 0.043 Cal*m^-1*K^-1.
a=d
In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.
h t t p s : / / w w w . y o u t u b e . c o m / w a t c h ? v = H k Q 7 _ o W q K p c
== Q== mc(delta)T == Q=thermal energy m= mass c=specific heat (ex. water is 4.184 J/goc) deltaT= change in temperature
Q = mct where q is the energy, m is the mass in kilograms, c is the specific heat in kelvins, and t is the change in temperature
That equation is, q(Joules) = mass * specific heat ( symbol is C ) * (delta, a triangle) change in temperature That is to say delta means, Temperature Final - Temperature Initial q is a constant and not subject to change as temperature is
You have to know mass in grams, energy (q) gained or lost in Joules, and change in temperature,ΔT, in degrees C. ΔT = Final temp - initial temp. The specific heat = q/(m)(ΔT) = J/g•oC
M. T. C. Cronin was born in 1963.
Q=cm(delta)T "Q" is the heat "C" is the specific heat "m" is the mass "(delta)T" is the change in temperature * just plug in what you have and then solve for what you don't have...and thats how you find the specific heat of a substance.
T= Tragical M= MarvelousC= Cat
There are six letters between M and T. They are n, o, p, q, r, and s. The midway point is in the middle between P and Q, so there is no one letter midway between M and T. If you must have an answer, it would be both P and Q.
The equation is q = mC∆T where q is the heat; m is the mass of water; C is the specific heat of water (1 cal/g/deg); and ∆T is the change in temperature.