That's not a question.
Q = (m)(c)(deltaT)
In chemistry, q (heat energy) can be calculated using the equation q m x c x T, where m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature.
To find the value of q in chemistry, one can use the formula q m c T, where q represents the heat energy, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature. By plugging in the known values for mass, specific heat capacity, and temperature change, one can calculate the value of q.
To find the grams of water, we first need to calculate the change in temperature of the water using the specific heat capacity of water (4.18 J/g°C). Delta T = Q / (m * C), where Q is the heat supplied (348 J), C is the specific heat capacity of water (4.18 J/g°C), and m is the mass of water in grams. Rearranging the formula to solve for mass, we get m = Q / (C * delta T). Plugging in the values, we find m = 348 / (4.18 * 5.2) ≈ 16.7 grams of water.
Without stating units, it is impossible to answer this question accurately. However, the equation you would need is q=mc∆T, where q is the heat flow (the 53.0 listed, likely Joules), m is the mass of the unknown metal (11.1, likely grams), c is the specific heat of the metal (the unknown you need to solve for), and ∆T is the change in temperature of the metal (24.1-13.0, likely Celcius). Rearranged to solve for specific heat, the question is c=q/m∆T.
The heat released can be calculated using the formula: Q = m * c * ΔT, where Q is the heat released, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Converting the units, the heat released is approximately 2.44 kJ.
The specific heat (c) can be calculated by rearranging the equation as c = Q / (m x T), where Q is the heat energy transferred, m is the mass of the substance, and T is the temperature change.
In chemistry, q (heat energy) can be calculated using the equation q m x c x T, where m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature.
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In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.
To get from the equation for energy, ( q = m \cdot C \cdot \Delta T ) (where ( q ) is energy, ( m ) is mass, ( C ) is specific heat capacity, and ( \Delta T ) is the change in temperature) to energy density, you divide the total energy ( q ) by the volume ( V ) of the material. This gives you energy density ( u ) as ( u = \frac{q}{V} = \frac{m \cdot C \cdot \Delta T}{V} ). Since mass ( m ) can also be expressed as density ( \rho ) multiplied by volume ( V ) (i.e., ( m = \rho \cdot V )), you can substitute to obtain: ( u = \rho \cdot C \cdot \Delta T ).
To find the value of q in chemistry, one can use the formula q m c T, where q represents the heat energy, m is the mass of the substance, c is the specific heat capacity, and T is the change in temperature. By plugging in the known values for mass, specific heat capacity, and temperature change, one can calculate the value of q.
To calculate the specific heat of ANFO (Ammonium Nitrate Fuel Oil), you can use the formula: ( Q = mc\Delta T ), where ( Q ) is the heat added, ( m ) is the mass of the ANFO, ( c ) is the specific heat, and ( \Delta T ) is the change in temperature. By rearranging the formula to solve for ( c ) gives ( c = \frac{Q}{m\Delta T} ). You would need to experimentally determine ( Q ) by measuring the heat energy supplied, ( m ) as the mass of ANFO, and ( \Delta T ) as the temperature change during the process.
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The equation for thermal energy is Q = mcΔT, where Q is the thermal energy transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
To find the mass of the water, you can use the formula ( q = mc\Delta T ), where ( q ) is the heat energy (213 J), ( m ) is the mass, ( c ) is the specific heat capacity of water (approximately 4.18 J/g°C), and ( \Delta T ) is the temperature change (8.2°C). Rearranging the formula to solve for mass gives ( m = \frac{q}{c\Delta T} ). Plugging in the values, ( m = \frac{213 , \text{J}}{4.18 , \text{J/g°C} \times 8.2 , \text{°C}} ), which calculates to approximately 6.3 grams.
The formula to find the specific heat of water ( Q ) is: ( Q = mc\Delta T ), where (m) is the mass of the water, (c) is the specific heat capacity of water, and ( \Delta T ) is the change in temperature of the water.
The formula to find thermal energy is: Q = mc∆T, where Q is the thermal energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ∆T is the change in temperature.