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q = mC∆T where q=heat; m=mass of water; C=sp.heat; ∆T=change in temp.q = (25.0g)(4.184 J/g/deg)(45 deg)

q = 4707 J of heat released

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Q: How much heat in kilojoules is released when 25.0 g of water is cooled from 85.0ºC to 40.0ºC The specific heat of water is 4.184 J(gC).?
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