Yes, the mass of a sample of water remains unchanged when it expands. This is because only its density and volume vary with temperature. As the temperature increases, two dependent changes occur: the volume of the water increases and the density decreases. These two changes happen in correlation with each other such that the mass remains exactly the same.
A second way of thinking about this problem is on a molecule scale. When heating water (composed of many H2O molecules) the number of the molecules in your sample doesn't change, nor does the mass of each molecule. Therefore there is no reason your sample's mass should change (unless you lose some water, which can be prevented by using a sealed container).
The concentration of chloroform in the drinking water sample can be expressed as 0.0015% by mass. This is because 15 ppm represents 0.0015% of the total mass of the sample.
The mass of 1 mL of water is 1 g.
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
density = mass / volume. so you need to weigh to find the mass. To find the volume submerse in water and record the displacement of water to find the volume.
The sample of water that contains the most heat energy is the 20 g sample at 10 degrees Celsius because it has double the mass of the 10 g sample. Heat energy is directly proportional to mass, so the sample with more mass will contain more heat energy.
The mass remain unchanged.
In order to determine the mass of the water sample, you would need to know the density of water. The density of water is approximately 1 g/cm3. Therefore, the mass of a 20 cm3 sample of water would be 20 grams (20 cm3 * 1 g/cm3 = 20 grams).
If you double the volume of a sample ... scoop up twice as much of it ... the mass of the sample always doubles. But the density of the substance doesn't change. Think about it: The density of some water out of my dog's water bowl is the same as the density of some water out of Lake Michigan.
The mass remain unchanged.
Density is an intensive quantity which means it is independent of size. This can be seen from the definition of density. Density = mass/volume So if the sample size increases than so does the mass, but the density remains unchanged.
Expands
Yes, when water evaporates, its mass does not decrease. The water molecules simply change from a liquid state to a gaseous state, but the total mass of the water remains the same.
The concentration of chloroform in the drinking water sample can be expressed as 0.0015% by mass. This is because 15 ppm represents 0.0015% of the total mass of the sample.
To determine the remaining mass of a 10-gram sample of (^{42}\text{K}) after 12.4 hours, we need to know its half-life. The half-life of (^{42}\text{K}) is approximately 12.36 hours. After 12.4 hours, which is slightly more than one half-life, the mass will be reduced to about half of the initial mass. Thus, approximately 5 grams of the original 10-gram sample will remain unchanged after 12.4 hours.
Initial water content in the soil sample can be calculated using the initial mass and final mass after drying. Initial water content = (Initial mass - Final mass) = 1.38 kg - 1.13 kg = 0.25 kg. This is the mass of water in the soil sample.
what?
The mass of 1 mL of water is 1 g.