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Yes, the mass of a sample of water remains unchanged when it expands. This is because only its density and volume vary with temperature. As the temperature increases, two dependent changes occur: the volume of the water increases and the density decreases. These two changes happen in correlation with each other such that the mass remains exactly the same.

A second way of thinking about this problem is on a molecule scale. When heating water (composed of many H2O molecules) the number of the molecules in your sample doesn't change, nor does the mass of each molecule. Therefore there is no reason your sample's mass should change (unless you lose some water, which can be prevented by using a sealed container).

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When water evaporates does its mass increase?

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What hapens to the density if both the volume and mass are doubled?

If you double the volume of a sample ... scoop up twice as much of it ... the mass of the sample always doubles. But the density of the substance doesn't change. Think about it: The density of some water out of my dog's water bowl is the same as the density of some water out of Lake Michigan.


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Why is the density of a substance independent of sample size?

Density is an intensive quantity which means it is independent of size. This can be seen from the definition of density. Density = mass/volume So if the sample size increases than so does the mass, but the density remains unchanged.


What happen to a given mass of water as it is cooled from 4° to 0°?

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When water evaporates does its mass decrease?

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If sample of drinking water was contaminated with 15 ppm by mass of chloroform then express in percent by mass?

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