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The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.
The reaction between dissolved barium chloride and dissolved potassium sulfate in water forms solid barium sulfate as a precipitate and soluble potassium chloride in the water solution. This is a double displacement reaction where the cations switch partners to form the products. Barium sulfate is insoluble in water, which causes it to precipitate out.
The ionization equation for potassium sulfate (K2SO4) in water is: K2SO4 (s) -> 2K+ (aq) + SO4^2- (aq)
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.
The reaction between dissolved barium chloride and dissolved potassium sulfate in water forms solid barium sulfate as a precipitate and soluble potassium chloride in the water solution. This is a double displacement reaction where the cations switch partners to form the products. Barium sulfate is insoluble in water, which causes it to precipitate out.
A dissolved sulfate ion is colorless. In solution, sulfate ions do not impart any color to the solution.
Granular potassium sulfate does not have a pH. A pH value can only be given to a solution.
The ionization equation for potassium sulfate (K2SO4) in water is: K2SO4 (s) -> 2K+ (aq) + SO4^2- (aq)
If it's molten or dissolved in water, it's an electrolyte.
The pH value of potassium sulfate, K2SO4, is neutral, around 7. This is because potassium sulfate dissociates in water to release potassium ions (K+) and sulfate ions (SO4^2-) which do not significantly affect the pH of the solution.
To determine if a solution contains potassium sulfate, you can perform a flame test. When a sample of the solution is heated in a flame, the potassium ions will emit a lilac flame color, which is characteristic of potassium compounds. This can help confirm the presence of potassium sulfate in the solution.
Potassium oxalate is soluble as are all potassium compounds.
Ammonium sulphate and potassium nitrate do not react. All that will happen is that the solution will contain separate ammonium, sulphate, potassium, and nitrate ions dissolved in an aqueous (water) solution.