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The mass containing 6.0x10^23 atoms depends on the element. For example, for carbon-12, 6.0x10^23 atoms would weigh approximately 12 grams.

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Au contains how many gold atoms?

This depends on the mass of the gold sample.


Which sample contains the same number of atoms as a gram atomic mass of he?

A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.


What is the relationship between the atomic mass of an element and a mole of that elements atoms?

The mole is the atomic weight expressed in grams.


Which contains more atoms 56g of Fe or 16g of S?

There are more atoms of sulfur in 16 grams than there are atoms of iron in 56 grams.


How many atoms are there in an element?

The number of atoms in an element depends on the element's atomic mass and the amount of the element present. One mole of an element contains approximately 6.022 x 10^23 atoms, known as Avogadro's number.


What is the number of manganese atoms that equal a mass of 54.94 g?

54.94g Manganese = 1mole = 6.023 x 1023 atoms


How many uranium atoms are in 6g of pure uranium?

To find the number of uranium atoms in 6g of pure uranium, we first need to calculate the molar mass of uranium, which is approximately 238.03 g/mol. Then, we use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the mass to number of atoms. So, 6g of uranium contains about 6.022 × 10^23 atoms.


What is the mass of 6.02 10 23 atoms of sulfur?

32g


How many atoms are present in 16g og Oxygen?

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What is the mass in grams of 1.50 x 10 23 atoms Mg?

1 mole of any substance contains 6.022 x 10^(23) atoms/molecules. We have 1.5 x 10^(23) atoms Hence moles = 1.5 x 10^(23) / 6.022 x 10^(23) = 0.24908... moles(Mg) Also remember the eq'n moles = mass(g) / Ar Algebraically rearrange mass(g) = moles X Ar mass = 0.24908... X 24.3 (Ar of Mg ; from Periodic Table) Mass = 6.0528... g ~ 6 g


What is the mass in g of 9.44x10 23 atoms of lithium?

To calculate the mass of 9.44x10^23 atoms of lithium, you can use the molar mass of lithium, which is approximately 6.94 g/mol. Divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass to get the mass in grams.


What is the Total mass of3.01 x 10 23 atoms of helium gas?

To find the total mass of 3.01 x 10^23 atoms of helium gas, you need to multiply the number of atoms by the atomic mass of helium. Helium's atomic mass is approximately 4 atomic mass units. So, the total mass would be 3.01 x 10^23 atoms * 4 amu.