The mass containing 6.0x10^23 atoms depends on the element. For example, for carbon-12, 6.0x10^23 atoms would weigh approximately 12 grams.
This depends on the mass of the gold sample.
The mole is the atomic weight expressed in grams.
There are more atoms of sulfur in 16 grams than there are atoms of iron in 56 grams.
The number of atoms in an element depends on the element's atomic mass and the amount of the element present. One mole of an element contains approximately 6.022 x 10^23 atoms, known as Avogadro's number.
54.94g Manganese = 1mole = 6.023 x 1023 atoms
This depends on the mass of the gold sample.
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
The mole is the atomic weight expressed in grams.
There are more atoms of sulfur in 16 grams than there are atoms of iron in 56 grams.
The number of atoms in an element depends on the element's atomic mass and the amount of the element present. One mole of an element contains approximately 6.022 x 10^23 atoms, known as Avogadro's number.
54.94g Manganese = 1mole = 6.023 x 1023 atoms
To find the number of uranium atoms in 6g of pure uranium, we first need to calculate the molar mass of uranium, which is approximately 238.03 g/mol. Then, we use Avogadro's number (6.022 x 10^23 atoms/mol) to convert the mass to number of atoms. So, 6g of uranium contains about 6.022 × 10^23 atoms.
32g
One mole of oxygen has a mass of 16 grams and contains 6.022 x 10^23 oxygen atoms. Therefore, 16 grams of oxygen will also contain 6.022 x 10^23 oxygen atoms.
1 mole of any substance contains 6.022 x 10^(23) atoms/molecules. We have 1.5 x 10^(23) atoms Hence moles = 1.5 x 10^(23) / 6.022 x 10^(23) = 0.24908... moles(Mg) Also remember the eq'n moles = mass(g) / Ar Algebraically rearrange mass(g) = moles X Ar mass = 0.24908... X 24.3 (Ar of Mg ; from Periodic Table) Mass = 6.0528... g ~ 6 g
To calculate the mass of 9.44x10^23 atoms of lithium, you can use the molar mass of lithium, which is approximately 6.94 g/mol. Divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass to get the mass in grams.
To find the total mass of 3.01 x 10^23 atoms of helium gas, you need to multiply the number of atoms by the atomic mass of helium. Helium's atomic mass is approximately 4 atomic mass units. So, the total mass would be 3.01 x 10^23 atoms * 4 amu.