To calculate the mass of 9.44x10^23 atoms of lithium, you can use the molar mass of lithium, which is approximately 6.94 g/mol. Divide the number of atoms by Avogadro's number to get the number of moles, then multiply by the molar mass to get the mass in grams.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
To find the number of lithium atoms, you would need to know the molar mass of lithium (6.94 g/mol) and then use the formula: Number of atoms = (0.01456 g / 6.94 g/mol) * Avogadro's number Avogadro's number is 6.022 x 10^23 atoms/mol.
Remember the Avogadro Number. 1 moles = 6.022 x 10^(23) atoms/molecules. So for 0.106 moles lithium it is 0.106 X 6.022 x 10^(23) = 6.38 x 10^(22) atoms (Li). or stringing it out 6,380,000,000,000,000,000,000 atoms
To determine the number of atoms in 54.9 grams of lithium hypochlorite, you first need to calculate the number of moles by dividing the given mass by the molar mass of LiClO. Then, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms.
Well, honey, if we're talking about lithium (Li) and you've got 55.2 grams of it, you're looking at approximately 7.4 x 10^23 atoms. That's a whole lotta Li atoms in your hands. Hope you've got a plan for all that atomic power!
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
Li atomic mass= 6.941g/mol= 4.9 moles of Li1.00 mol = 6.02 x 1023 atoms4.9 mol Li = 2.95 x 1024 atoms= 3.0 x 1024 atoms
2.32
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To calculate the number of atoms in a sample of lithium, you first find the moles using the molar mass. Lithium's molar mass is approximately 6.94 g/mol. Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms.
To determine the number of atoms in 12.7 grams of lithium, you need to first calculate the number of moles using the molar mass of lithium (6.94 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert from moles to atoms.
To find the number of lithium atoms, you would need to know the molar mass of lithium (6.94 g/mol) and then use the formula: Number of atoms = (0.01456 g / 6.94 g/mol) * Avogadro's number Avogadro's number is 6.022 x 10^23 atoms/mol.
Remember the Avogadro Number. 1 moles = 6.022 x 10^(23) atoms/molecules. So for 0.106 moles lithium it is 0.106 X 6.022 x 10^(23) = 6.38 x 10^(22) atoms (Li). or stringing it out 6,380,000,000,000,000,000,000 atoms
To determine the number of atoms in 54.9 grams of lithium hypochlorite, you first need to calculate the number of moles by dividing the given mass by the molar mass of LiClO. Then, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms.
To find the number of atoms in 4 moles of lithium, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Therefore, in 4 moles of lithium, the number of atoms is (4 \times 6.022 \times 10^{23} = 2.409 \times 10^{24}) atoms.
Well, honey, if we're talking about lithium (Li) and you've got 55.2 grams of it, you're looking at approximately 7.4 x 10^23 atoms. That's a whole lotta Li atoms in your hands. Hope you've got a plan for all that atomic power!
I assume you mean 97.9 grams lithium. 97.9 grams lithium (1 mole Li/6.941 grams)(6.022 X 10^23/1 mole Li) = 8.49 X 10^24 atoms of lithium ---------------------------------------