4 g (1 mole) of helium will occupy 22.414 liters.
So, 15 g will occupy 84.05 liters
The volume occupied by a substance depends on its density. If you know the density of the substance, you can calculate the volume using the formula: Volume = Mass / Density. Without the density information, you cannot accurately determine the volume occupied by 7.75 g of the substance.
To find the volume, you divide the mass by the density. In this case, the volume would be 5 ml (15 g ÷ 3 ml).
The mass of 43,7 L of helium at STP is 7.8 g.
The volume of gold can be calculated by dividing the mass by the density. In this case, 450 g divided by 19 g/cm^3 gives a volume of 23.68 cm^3. Therefore, 450 g of gold occupies a volume of 23.68 cm^3.
You will mean 15 cc or cubic centimeter. The answer is 4g / cc ( 60 g divide 15 cc )
4 g of helium occupies 22.414 liters So, 0.8 g will occupy 4.483 liters
The volume occupied by a substance depends on its density. If you know the density of the substance, you can calculate the volume using the formula: Volume = Mass / Density. Without the density information, you cannot accurately determine the volume occupied by 7.75 g of the substance.
* Calculate the volume of the ballon * Calculate the weight of the helium: G= V x 0,1786 (the helium density in g/L) * Add the weight of the balloon material (rubber, plastic, etc.)
To find the volume occupied by 16.4 g of mercury, we use the density of mercury, which is approximately 13.6 g/cm³. Using the formula ( \text{Volume} = \frac{\text{Mass}}{\text{Density}} ), we calculate the volume: [ \text{Volume} = \frac{16.4 \text{ g}}{13.6 \text{ g/cm}^3} \approx 1.21 \text{ cm}^3. ] Thus, 16.4 g of mercury occupies about 1.21 cm³.
The volume of any gas at STP (standard temperature and pressure) is 22.4 L/mol. The molar mass of helium is 4.0026 g/mol. So, 84.6 grams of helium would be 84.6/4.0026 = 21.1 mol. Therefore, the volume of 84.6 grams of helium at STP would be 21.1 mol * 22.4 L/mol = 472.64 L.
To calculate the mass of helium, you would need to know the density of helium (0.1785 g/L at 0°C and 1 atm). You can use the formula: mass = density x volume. In this case, mass = 0.1785 g/L x 6.3 L = 1.125 g.
35.2 / 1.6 = 22 mL
To find the volume, you divide the mass by the density. In this case, the volume would be 5 ml (15 g ÷ 3 ml).
Density = mass/volume = 36/15 = 2.4 g per cm3
The mass of 43,7 L of helium at STP is 7.8 g.
To double the volume of the balloon, you would need to add an additional 8.00 g of helium gas. This is because the ideal gas law states that the volume of a gas is directly proportional to the amount of gas present, assuming constant temperature and pressure. So, if you double the amount of gas, you double the volume of the balloon.
Mass = 15 gm Volume = 2 cubic cm Density = Mass/Volume = 15/2 = 7 and 1/2 or 7.5 g per cm3