The volume of 1 mole of water is approximately 18 milliliters.
The molarity of 1 mol of Na3PO4 in 2 L of water is 0.5 M. This is calculated by dividing the number of moles of solute (1 mol) by the volume of solution in liters (2 L).
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, with 1/2 mol of Cu(NO3)2 in 1/2 L of water, the molarity is 1 M (1 mol/L).
The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.
The molar volume of water is 18.02 cm/mol at standard temperature and pressure. This volume affects the density, compressibility, and other physical properties of water.
4 mol/0.800 kg
The molarity of 1 mol of Na3PO4 in 2 L of water is 0.5 M. This is calculated by dividing the number of moles of solute (1 mol) by the volume of solution in liters (2 L).
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL
The equation you will need is: Mol of substance 1 * volume of substance 1 = Mol of substance 2 * volume of substance 2
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, with 1/2 mol of Cu(NO3)2 in 1/2 L of water, the molarity is 1 M (1 mol/L).
The molarity of a solution with 3 mol of glucose in 6 kg of water cannot be determined without knowing the volume of the solution. Molarity is defined as the amount of solute (in mol) divided by the volume of the solution in liters. Without the volume, the molarity of the solution cannot be calculated.
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
Exactly the same number of mols. 1 mol of oxigen atoms produces 1 mol of water molecules.
The molar volume of water is 18.02 cm/mol at standard temperature and pressure. This volume affects the density, compressibility, and other physical properties of water.
4 mol/0.800 kg
You need 40.01 g NaOH per liter volume of the solution. This is not the same as adding 1 liter of water to 40.01 g of NaOH. The NaOH must be put in the flask and the volume brought up to 1 liter total volume (NaOH volume + water volume).
The molar volume of liquid water at standard temperature and pressure is approximately 18.07 cm/mol.
3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL