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What is the molarity of 4 mol of NaOH dissolved in 2L of water?
The molarity can be calculated by dividing the number of moles of solute by the volume of solution in liters. In this case, the molarity would be 2 M (4 mol NaOH / 2 L water).
What is the molarity of 80g NaOH dissolved in 1L of water?
To find the molarity, we first need to calculate the number of moles of NaOH. The molar mass of NaOH is 40 g/mol (sodium=23g/mol, oxygen=16g/mol, hydrogen=1g/mol). Thus, 80g NaOH is 2 moles (80g / 40g/mol). Given 1L of solution, the molarity is 2 moles / 1 L = 2 M.
What is the molarity of 4mol of NaOH dissolved in 2L of water?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
What is the molarity 416.48g BaCl2 dissolved in 2 L of water?
To find the molarity, first calculate the number of moles of BaCl2 by dividing the mass by its molar mass (Ba: 137.33 g/mol, Cl: 35.45 g/mol). Then, divide the number of moles by the volume of water in liters to get the molarity. In this case, the molarity of 416.48 g of BaCl2 dissolved in 2 L of water is approximately 3.02 M.
What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.
What is the molarity of 4 mol of NaOH dissolved in 2L of water?
The molarity can be calculated by dividing the number of moles of solute by the volume of solution in liters. In this case, the molarity would be 2 M (4 mol NaOH / 2 L water).
What is molarity pure water?
Pure water does not have a molarity because it is not a solute dissolved in a solvent. However, under standard conditions, the molarity of pure water is 55.56 mol/L, which corresponds to its concentration of water molecules.
If 24g of table salt dissolved in 2liters of water what is the concentration of salt in the form of a ratio?
Concentration = Molarity = mol/L24 g NaCl = ?? mol NaCl?? mol NaCl/2 L water = ?? M (M is unit of molarity)
What is the molarity of 80g NaOH dissolved in 1L of water?
To find the molarity, we first need to calculate the number of moles of NaOH. The molar mass of NaOH is 40 g/mol (sodium=23g/mol, oxygen=16g/mol, hydrogen=1g/mol). Thus, 80g NaOH is 2 moles (80g / 40g/mol). Given 1L of solution, the molarity is 2 moles / 1 L = 2 M.
What is the molarity of 4mol of NaOH dissolved in 2L of water?
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution with 4 mol of NaOH dissolved in 2 L of water would be 2 M.
What is the molarity 416.48g BaCl2 dissolved in 2 L of water?
To find the molarity, first calculate the number of moles of BaCl2 by dividing the mass by its molar mass (Ba: 137.33 g/mol, Cl: 35.45 g/mol). Then, divide the number of moles by the volume of water in liters to get the molarity. In this case, the molarity of 416.48 g of BaCl2 dissolved in 2 L of water is approximately 3.02 M.
What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?
The molarity of the solution is 3 M. This is calculated by dividing the moles of solute by the volume of solution in liters. In this case, 6 moles divided by 2 liters equals a molarity of 3 M.
What is the molarity of a 0.142 M Na3 PO4 solution that has a density of 1.015 g m L Show all the steps?
To find the molarity of the Na3PO4 solution, we first need to calculate the molar mass of Na3PO4: Na: 22.99 g/mol P: 30.97 g/mol O: 16.00 g/mol Total molar mass = 22.99 * 3 + 30.97 + 16.00 * 4 = 163.94 g/mol Next, we find the concentration in mol/L: 0.142 M Na3PO4 = 0.142 mol/L Then, we convert the density from g/mL to g/L: 1.015 g/mL * 1000 mL/L = 1015 g/L Finally, we calculate the molarity using the formula: molarity = (density / molar mass) * concentration molarity = (1015 g/L / 163.94 g/mol) * 0.142 mol/L ≈ 0.88 M
What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What is the molarity of 2 mol of KI dissolved in 1 L water?
The moLaRity of this solution ie 2 mol/L or 2M KI (it is a 'two molair potassium iodide' solution)
How many moles of sodium ions are present in 2.50 L of 0.300 M Na3PO4?
There are 0.75 moles of sodium ions present in 2.50 L of 0.300 M Na3PO4. Each formula unit of Na3PO4 has 3 sodium ions. So, for every mole of Na3PO4, there are 3 moles of sodium ions. Calculating the moles of sodium ions: 2.5 L * 0.300 mol/L * 3 mol Na+ / 1 mol Na3PO4 = 0.75 moles of Na+.
What is molarity of 720g of pure water?
The molarity of pure water is 55.56 mol/L.
