The oxidation number for iodine in iodine pentoxide (I2O5) is +5. This is determined by taking into account the overall charge of the compound and the known oxidation number of oxygen atoms in a molecule.
In ICl (iodine chloride), iodine has an oxidation number of +1 because chlorine typically has an oxidation number of -1.
The oxidation number for iodine monoxide (IO) is +1 for iodine and -2 for oxygen.
The oxidation number of iodine in IF is +1 because fluorine is more electronegative than iodine and will take on a charge of -1. Since the compound is neutral, the oxidation number of iodine must be +1 to balance the -1 charge of fluorine.
In IF7, Fluorine is more electronegative than Iodine, so Fluorine will have an oxidation number of -1. Since there are 7 Fluorine atoms bonded to the Iodine atom, their total oxidation number is -7. To find the oxidation number of Iodine, you would set up an equation: I + (-7) = 0. Therefore, the oxidation number of Iodine in IF7 is +7.
The oxidation number of Iodine (I) in HI (hydroiodic acid) is -1. In binary compounds with hydrogen, hydrogen is assigned an oxidation number of +1. Therefore, the oxidation number of Iodine must be -1 in order for the overall compound to be neutral.
In ICl (iodine chloride), iodine has an oxidation number of +1 because chlorine typically has an oxidation number of -1.
The oxidation number for iodine monoxide (IO) is +1 for iodine and -2 for oxygen.
The oxidation number of iodine in IF is +1 because fluorine is more electronegative than iodine and will take on a charge of -1. Since the compound is neutral, the oxidation number of iodine must be +1 to balance the -1 charge of fluorine.
In IF7, Fluorine is more electronegative than Iodine, so Fluorine will have an oxidation number of -1. Since there are 7 Fluorine atoms bonded to the Iodine atom, their total oxidation number is -7. To find the oxidation number of Iodine, you would set up an equation: I + (-7) = 0. Therefore, the oxidation number of Iodine in IF7 is +7.
zero for iodine
The oxidation number of Iodine (I) in HI (hydroiodic acid) is -1. In binary compounds with hydrogen, hydrogen is assigned an oxidation number of +1. Therefore, the oxidation number of Iodine must be -1 in order for the overall compound to be neutral.
The oxidation number of iodine in the iodate ion (IO3-) is +5. Each oxygen atom has an oxidation number of -2, giving a total of -6 for the three oxygen atoms. To neutralize the charge of -1 on the ion, the oxidation number of iodine must be +5.
IO2 is the chemical formula of iodine dioxide.
The oxidation number of Iodine (I) in HIO2 is +3. This is because the sum of the oxidation numbers in a neutral molecule must add up to zero, and since hydrogen is typically assigned an oxidation number of +1, and oxygen is typically assigned an oxidation number of -2, the oxidation number of Iodine is +3.
+5. F is always -1
The oxidation number of phosphorus in phosphorus pentoxide (P4O10) is +5. This is because each oxygen atom has an oxidation number of -2, leading to a total charge of -10 for the oxygen atoms in the compound. The sum of the oxidation numbers in a neutral compound like P4O10 is zero, so the oxidation number of phosphorus must be +5 to balance the overall charge.
The oxidation number of a free element is zero. However, the oxidation number of elements (e.g. iodine) in compounds will not be zero. The actual oxidation number/state can be deduced if the chemical formula of the compound is given.