-1 for each Fluorine
+7 for Iodine
The oxidation number of iodine in IF7 is +7. This is because fluorine is more electronegative than iodine, so each fluorine atom in the compound carries an oxidation number of -1. Since there are 7 fluorine atoms in IF7, the total charge from fluorine is -7, which means iodine must have an oxidation number of +7 to balance the charge.
BrF3: trigonal bipyramidal IF7: pentagonal bipyramidal
The name for the covalent compound IF7 is iodine heptafluoride.
Covalent. Iodine and fluorine are both nonmetals.
The oxidation number of a free element is zero. However, the oxidation number of elements (e.g. iodine) in compounds will not be zero. The actual oxidation number/state can be deduced if the chemical formula of the compound is given.
The oxidation number of iodine in IF7 is +7. This is because fluorine is more electronegative than iodine, so each fluorine atom in the compound carries an oxidation number of -1. Since there are 7 fluorine atoms in IF7, the total charge from fluorine is -7, which means iodine must have an oxidation number of +7 to balance the charge.
BrF3: trigonal bipyramidal IF7: pentagonal bipyramidal
The name for the covalent compound IF7 is iodine heptafluoride.
IF7 exists because iodine can accommodate a higher oxidation state, allowing it to form a stable compound with seven fluorine atoms due to the strong electronegativity and small size of fluorine. In contrast, bromine does not have the same ability to stabilize a +7 oxidation state; its larger size and lower electronegativity make it less capable of forming a stable compound with seven bromine atoms. Consequently, IBr7 is not found because bromine cannot effectively achieve or maintain this high oxidation state.
Covalent. Iodine and fluorine are both nonmetals.
The oxidation number of a free element is zero. However, the oxidation number of elements (e.g. iodine) in compounds will not be zero. The actual oxidation number/state can be deduced if the chemical formula of the compound is given.
To determine the number of molecules in 15.9 g of IF7 (iodine heptafluoride), first calculate the molar mass of IF7. The molar mass is approximately 144.9 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, ( \text{number of moles} = \frac{15.9 , \text{g}}{144.9 , \text{g/mol}} \approx 0.1096 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) to find the number of molecules: (0.1096 , \text{mol} \times 6.022 \times 10^{23} \approx 6.60 \times 10^{22}) molecules of IF7.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.