answersLogoWhite

0

IF7 exists because iodine can accommodate a higher oxidation state, allowing it to form a stable compound with seven fluorine atoms due to the strong electronegativity and small size of fluorine. In contrast, bromine does not have the same ability to stabilize a +7 oxidation state; its larger size and lower electronegativity make it less capable of forming a stable compound with seven bromine atoms. Consequently, IBr7 is not found because bromine cannot effectively achieve or maintain this high oxidation state.

User Avatar

AnswerBot

1mo ago

What else can I help you with?

Related Questions

What are the shapes of the following molecules using vsepr thory of BrF3and IF7?

BrF3: trigonal bipyramidal IF7: pentagonal bipyramidal


What is the formula for iodine heptabromide?

IBr7 is the formula for iodine heptabromide.


What is the name for the covalent compounds IF7?

The name for the covalent compound IF7 is iodine heptafluoride.


Is IF7 an ionic or covalent?

Covalent. Iodine and fluorine are both nonmetals.


What is the name of IF7's molecular shape?

The name of IF7's molecular shape is pentagonal bipyramidal.


What adjective best describes the solid compound IF7?

Covalent Network


What is the name of the molecular compound IF7?

iodine heptafluoride


What is the Oxidation number on IF7?

The oxidation number of iodine in IF7 is +7. This is because fluorine is more electronegative than iodine, so each fluorine atom in the compound carries an oxidation number of -1. Since there are 7 fluorine atoms in IF7, the total charge from fluorine is -7, which means iodine must have an oxidation number of +7 to balance the charge.


IF7 is the chemical formula for what?

IF7 is the chemical formula for iodine heptafluoride. It consists of one iodine atom and seven fluorine atoms. It is a colorless, volatile solid compound that is highly reactive.


What is the oxidation number of you in IF7?

In IF7, Fluorine is more electronegative than Iodine, so Fluorine will have an oxidation number of -1. Since there are 7 Fluorine atoms bonded to the Iodine atom, their total oxidation number is -7. To find the oxidation number of Iodine, you would set up an equation: I + (-7) = 0. Therefore, the oxidation number of Iodine in IF7 is +7.


What is the name of a compound with the formula IF7?

Iodine Heptafluoride


How many molecules are there in 15.9 g of IF7?

To determine the number of molecules in 15.9 g of IF7 (iodine heptafluoride), first calculate the molar mass of IF7. The molar mass is approximately 144.9 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, ( \text{number of moles} = \frac{15.9 , \text{g}}{144.9 , \text{g/mol}} \approx 0.1096 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) to find the number of molecules: (0.1096 , \text{mol} \times 6.022 \times 10^{23} \approx 6.60 \times 10^{22}) molecules of IF7.