PtO2 is ionic
no. it only has ionic as far as i know.
Ionic solids are not dissociated in ions.
MgBr2 is an ionic compound (salt: magnesium bromide)
IF7 exists because iodine can accommodate a higher oxidation state, allowing it to form a stable compound with seven fluorine atoms due to the strong electronegativity and small size of fluorine. In contrast, bromine does not have the same ability to stabilize a +7 oxidation state; its larger size and lower electronegativity make it less capable of forming a stable compound with seven bromine atoms. Consequently, IBr7 is not found because bromine cannot effectively achieve or maintain this high oxidation state.
Covalent. Iodine and fluorine are both nonmetals.
BrF3: trigonal bipyramidal IF7: pentagonal bipyramidal
The name for the covalent compound IF7 is iodine heptafluoride.
The name of IF7's molecular shape is pentagonal bipyramidal.
Iodine heptafluoride (IF7) is held together by covalent bonds. It is a molecular compound composed of iodine and fluorine atoms that share electrons to form covalent bonds, rather than transferring electrons to form ionic bonds.
iodine heptafluoride
Covalent Network
The oxidation number of iodine in IF7 is +7. This is because fluorine is more electronegative than iodine, so each fluorine atom in the compound carries an oxidation number of -1. Since there are 7 fluorine atoms in IF7, the total charge from fluorine is -7, which means iodine must have an oxidation number of +7 to balance the charge.
IF7 is the chemical formula for iodine heptafluoride. It consists of one iodine atom and seven fluorine atoms. It is a colorless, volatile solid compound that is highly reactive.
In IF7, Fluorine is more electronegative than Iodine, so Fluorine will have an oxidation number of -1. Since there are 7 Fluorine atoms bonded to the Iodine atom, their total oxidation number is -7. To find the oxidation number of Iodine, you would set up an equation: I + (-7) = 0. Therefore, the oxidation number of Iodine in IF7 is +7.
Iodine Heptafluoride
To determine the number of molecules in 15.9 g of IF7 (iodine heptafluoride), first calculate the molar mass of IF7. The molar mass is approximately 144.9 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, ( \text{number of moles} = \frac{15.9 , \text{g}}{144.9 , \text{g/mol}} \approx 0.1096 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) to find the number of molecules: (0.1096 , \text{mol} \times 6.022 \times 10^{23} \approx 6.60 \times 10^{22}) molecules of IF7.