It's 399g.
The compound contains 1 cesium atom (Cs) and 1 oxygen atom (O). The molar mass of cesium is about 133.0 g/mol and oxygen is about 16.0 g/mol. Calculating the molar mass of Cs: (0.89 * 133.0 g/mol) = 118.37 g/mol Calculating the molar mass of O: (0.11 * 16.0 g/mol) = 1.76 g/mol Adding the molar masses together: 118.37 g/mol + 1.76 g/mol = 120.13 g/mol Thus, the molecular formula is CsO.
The molar mass of the compound is 298 g/mol. To find the molecular formula, we need to calculate the molar mass of Cs and O; Cs has a molar mass of approximately 132.91 g/mol, and O has a molar mass of approximately 16 g/mol. Using these values, we can determine that the compound's molecular formula is Cs11O11.
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
Molar mass of B10H14 = 122.22116 g/mol
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
The molar mass of Cesium Chloride (CsCl) is 168.36 g/mol. This is calculated by adding the molar mass of cesium (Cs) which is 132.91 g/mol and chlorine (Cl) which is 35.45 g/mol.
The molar mass of cesium (Cs) is approximately 132.91 g/mol. Therefore, the mass of 3.00 mol of cesium would be 3.00 mol x 132.91 g/mol = 398.73 g.
The molar mass of cesium (Cs) is approximately 133 g/mol. Therefore, the mass of 3.00 mol of cesium would be 3.00 mol x 133 g/mol = 399 g.
The molar mass of cesium (Cs) is approximately 132.91 g/mol. Since the chemical formula Cs₂ indicates there are two cesium atoms, the molar mass of Cs₂ is calculated as 2 × 132.91 g/mol, which equals approximately 265.82 g/mol.
Molar mass of Cesium oxide (Cs2O) is 281.81 g/mol
The compound contains 1 cesium atom (Cs) and 1 oxygen atom (O). The molar mass of cesium is about 133.0 g/mol and oxygen is about 16.0 g/mol. Calculating the molar mass of Cs: (0.89 * 133.0 g/mol) = 118.37 g/mol Calculating the molar mass of O: (0.11 * 16.0 g/mol) = 1.76 g/mol Adding the molar masses together: 118.37 g/mol + 1.76 g/mol = 120.13 g/mol Thus, the molecular formula is CsO.
The atomic mass is the mass in grams of one mole of the atoms concerned. Thus, 5 X 132.9 = 664.5 grams.
One atom of cesium has a mass of 132.9054 amu, and one mole of cesium has a mass of 132.9054 grams, so five moles of cesium has a mass of 664.527 grams.Multiplying the mass of a particle (which can be an atom, molecule, etc.) by Avogadro's number (6.022x1023, the number of particles of a substance in 1 mole) will give you the mass of a mole of that particle, or molar mass, in grams. Avogadro's number is special because the molar mass of a substance will be the same number as its atomic mass, only in grams!
The molar mass of the compound is 298 g/mol. To find the molecular formula, we need to calculate the molar mass of Cs and O; Cs has a molar mass of approximately 132.91 g/mol, and O has a molar mass of approximately 16 g/mol. Using these values, we can determine that the compound's molecular formula is Cs11O11.
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
The molar mass of PbSO4 (lead(II) sulfate) is approximately 303.3 g/mol. This can be calculated by adding the molar masses of each element in the compound: lead (Pb) has a molar mass of 207.2 g/mol, sulfur (S) has a molar mass of 32.1 g/mol, and oxygen (O) has a molar mass of 16.0 g/mol.
Molar mass of B10H14 = 122.22116 g/mol