The answer is 399 grams
The molar mass of Cesium Chloride (CsCl) is 168.36 g/mol. This is calculated by adding the molar mass of cesium (Cs) which is 132.91 g/mol and chlorine (Cl) which is 35.45 g/mol.
One atom of cesium has a mass of 132.9054 amu, and one mole of cesium has a mass of 132.9054 grams, so five moles of cesium has a mass of 664.527 grams.Multiplying the mass of a particle (which can be an atom, molecule, etc.) by Avogadro's number (6.022x1023, the number of particles of a substance in 1 mole) will give you the mass of a mole of that particle, or molar mass, in grams. Avogadro's number is special because the molar mass of a substance will be the same number as its atomic mass, only in grams!
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
To find the mass of 0.500 mol of dichlorodifluoromethane (CCl2F2), you need to calculate the molar mass of the compound. The molar mass of CCl2F2 is 120.91 g/mol. Therefore, 0.500 mol of CCl2F2 would have a mass of 0.500 mol x 120.91 g/mol = 60.455 g.
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
The molar mass of cesium (Cs) is approximately 133 g/mol. Therefore, the mass of 3.00 mol of cesium would be 3.00 mol x 133 g/mol = 399 g.
The molar mass of cesium (Cs) is approximately 132.91 g/mol. Therefore, the molar mass of 3.00 mol of cesium would be 3.00 mol x 132.91 g/mol = 398.73 grams.
The molar mass of Cesium Chloride (CsCl) is 168.36 g/mol. This is calculated by adding the molar mass of cesium (Cs) which is 132.91 g/mol and chlorine (Cl) which is 35.45 g/mol.
The atomic mass is the mass in grams of one mole of the atoms concerned. Thus, 5 X 132.9 = 664.5 grams.
Molar mass of Cesium oxide (Cs2O) is 281.81 g/mol
399
One atom of cesium has a mass of 132.9054 amu, and one mole of cesium has a mass of 132.9054 grams, so five moles of cesium has a mass of 664.527 grams.Multiplying the mass of a particle (which can be an atom, molecule, etc.) by Avogadro's number (6.022x1023, the number of particles of a substance in 1 mole) will give you the mass of a mole of that particle, or molar mass, in grams. Avogadro's number is special because the molar mass of a substance will be the same number as its atomic mass, only in grams!
The compound contains 1 cesium atom (Cs) and 1 oxygen atom (O). The molar mass of cesium is about 133.0 g/mol and oxygen is about 16.0 g/mol. Calculating the molar mass of Cs: (0.89 * 133.0 g/mol) = 118.37 g/mol Calculating the molar mass of O: (0.11 * 16.0 g/mol) = 1.76 g/mol Adding the molar masses together: 118.37 g/mol + 1.76 g/mol = 120.13 g/mol Thus, the molecular formula is CsO.
The gram atomic mass of cesium is 132.905 and that of nitrogen is 14.0067. The formula of the compound shows that there are three atoms of cesium for each atom of nitrogen. Therefore, the percent of cesium in the compound is: 100{3(132.905)/[3(132.905) + 14.0067]} or 96.6063 % cesium, to the justified number of significant digits. By difference the per cent nitrogen is 3.3937.
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
To find the mass of the solution needed, we first calculate the molar mass of CH3CO2Na which is 82.03 g/mol. For 0.150 mol of CH3CO2Na, the mass required would be 0.150 mol x 82.03 g/mol = 12.31 g. The mass of the 0.500 M solution can be found using the formula: mass = moles x molarity = 0.150 mol x 82.03 g/mol / 0.500 mol/L = 24.61 g.