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What mass in grams of a 0.500 m solution of ch3co2na in water would you use to obtain 0.150mol of ch3co2na?
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∙ 11y ago
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∙ 11y ago
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A solution has a density of 1.50 grams per milileter at 25.0 degrees Celsius How many grams are needed to obtain 5.00 ml of the solution?
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
How many milliliters of an aqueous solution of 0.149 M ammonium acetate is needed to obtain 16.9 grams of the salt?
The answer is 1 471,5 mL.
How many milliliters of an aqueous solution of 0.123 M cobalt(II) sulfate is needed to obtain 3.14 grams of the salt?
164,7 mL are needed.
If the percentage for a solute is 4 per cent and the mass of the solution is 200 grams what is the mass of the solute in solution?
200 grams of solution will contain 200 x 4% or 200 x 0.04 = 8.0 total grams of solute.
An iron ore sample is found to be 35.00 percent Fe by mass How many grams of ore is needed to obtain 454.0 grams of Fe?
The number of grams of ore that is needed to obtain 454.0 grams of Fe is 1297 grams. The answer was achieved by dividing 454.0 grams by 35 percent.
How many grams of sugar must be added to 60 grams of a solution that is 32 percent sugar to obtain a solution that is 50 percent sugar?
40.8 grams
How many grams of IKI would to take to obtain a 100mL solution of 0.300 M IKI?
It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.
How many grams of IKI would it take to obtain a 100mL solution of 0.300 M IKI?
It would be 12.6g of IKI to obtain the 100mL solution of 0.300 M IKI.
A solution has a density of 1.50 grams per milileter at 25.0 degrees Celsius How many grams are needed to obtain 5.00 ml of the solution?
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
A druggist has a 6 solution and also a 15 solution of a certain medicinehow much of the stronger solution must be add to a liter of the weaker to obtain a 10 solution?
The answer is 0.8 L: Let's think of a '6/15 solution' as meaning 6/15 grams per litre, and the solution we're trying to obtain is 10 grams/litre. In our final solution, we'll have 6 grams resulting from the one litre of weaker solution, and 15v grams from the stronger (where v is the volume of stronger added). Deviding this total mass by the total volume of the solution, we arrive at the wanted concentration of 10 grams/litre. Algebraicly: (15v + 6)/(1+v) litres = 10 15v + 6 = 10 + 10v 5v = 4 v = 4/5 = 0.8 L Hope this helps.
How many ml of a 0.124 m aqueous solution of nickel fluoride must be taken to obtain 4.36 grams of the salt?
The answer is 364 mL.
How many milliliters of an aqueous solution of 0.149 M ammonium acetate is needed to obtain 16.9 grams of the salt?
The answer is 1 471,5 mL.
How many milliliters of an aqueous solution of 0.123 M cobalt(II) sulfate is needed to obtain 3.14 grams of the salt?
164,7 mL are needed.
A solution in a dish contains 3.0 grams of salt dissolved in 100 grams of water if 50 grams of the water evaporatewhat is the solution?
mixture
If a salt solution has a specific gravity of 1.15 and a volume of 425mL what is the mass in grams of the solution?
489 grams
What is the percentage by mass of salt solution prepared by dissolving 11 grams of salt in 80 grams of solution with solution?
The percent concentration is 13,75 %.
What is meant by the mass mass percent concentration of a solution?
This is (mass of solute) divided by (mass of total solution) expressed as a percentage. The solute is what you are dissolving into the solution. Example: you have 90 grams of water, and you add 10 grams of salt (sodium chloride). The water is the solvent, sodium chloride is the solute, and the solution is salt water. 90 grams + 10 grams = 100 grams (mass of total solution). (10 grams) / (100 grams) = 0.1 --> 10% mass mass percent concentration.
