Q = I x t
Calculate the quantity of electricity, Q, obtained when a current of 25 amps runs for 1 minute.
Q = ? C
I = 25 A
t = 1 minute = 60 seconds
Q = 25 x 60 = 1,500 C
Calculate the current needed to provide 30,000 coulombs of electricity in 5 minutes.
Q = 30,000 C
I = ? A
t = 5 minutes = 5 x 60 = 300 seconds
I = Q ÷ t = 30,000 ÷ 300 = 100 amps
Calculate the time required to produce 12,000 C of electricity using a current of 10 amps.
Q = 12,000 C
I = 10 A
t = ?
t = Q ÷ t = 12,000 ÷ 10 = 1,200 seconds = 1,200 ÷ 60 = 20 minutes
Calculate the quantity of electricity obtained from 2 moles of electrons
Q = n x F
Q = ?
n = 2 mol
F = 96,500 C mol-1
Q = 2 x 96,500 = 193,000 C
Calculate the moles of electrons obtained from 250 C of electricity
n(e) = ? mol
Q = 250 C
F = 96,500 C mol-1
n(e) = 250 ÷ 96,500 = 2.59 x 10-3 mol
Ag+ + e -----> Ag(s)
moles of Ag(s) deposited, n(Ag) = moles of electrons required, n(e)
moles of Ag = n(Ag) = mass ÷ MM
mass Ag deposited = 56g
MM = 107.9 g mol-1 (from Periodic Table)
n (Ag) 56 ÷ 107.9 = 0.519 mol = n(e)
Q = ? C
n(e) = 0.519 mol
F = 96,500 C mol-1
Q = 0.519 x 96,500 = 50,083.5 C
Q = 50,083.5 C
I = 4.5 A
t = 50,083.5 ÷ 4.5 = 11,129.67 seconds
t = 11,129.67 ÷ 60 = 185.5 minutes
t = 185.5 ÷ 60 = 3.1 hours
I = 0.50 A
t = 10 seconds
Q = 0.50 x 10 = 5.0 C
Q = 5.0 C
F = 96,500 C mol-1
n(e) = 5.0 ÷ 96,500 = 5.18 x 10-5 mol
Cu2+ + 2e -----> Cu(s)
1 mole of copper is deposited from 2 moles electrons
n(Cu) = ½n(e) = ½ x 5.18 x 10-5 = 2.59 x 10-5 mol
MM = 63.55 g mol-1 (from Periodic Table)
mass (Cu) = (2.59 x 10-5) x 63.55 = 1.65 x 10-3 g = 1.65 mg
Calculate the minimum number of kilowatt-hours of electricity needed to produce the sodium metal.
Write the equation for the electrolysis of Na+:
Na+ + e -----> Na(s)
moles of Na(s) = moles of electrons used n(e)
n(e) = n(Na) = mass ÷ MM
mass = 1kg = 1,000g
MM = 22.99 g mol-1 (from Periodic Table)
n(e) = 1,000 ÷ 22.99 = 43.497 mol
n(e) = 43.497 mol
F = 96,500 C mol-1
Q = n(e) x F = 43.497 x 96,500 = 4.2 x 106 C
Q = 4.2 x 106
V = 4.5 V
E = 4.2 x 106 x 4.5 = 1.89 x 107 J
E = (1.89 x 107) ÷ (3.6 x 106) = 5.25 kWH
In copper electrolysis, Faraday's law is used to calculate the amount of copper deposited on the cathode during electrolysis based on the current passing through the circuit and the duration of the electrolysis process. This law states that the amount of substance deposited on an electrode is directly proportional to the quantity of electricity passed through the solution. By knowing the molar mass of copper and the charge of an electron, the amount of copper deposited can be accurately determined using Faraday's law.
An electrolysis process is based upon movement and flow of ions. More is the solution dilute, more is the movement of ions and more is the conductance of solution. Thus, when the solution is dilute more copper ions flow to the electrode and get deposited there
In electrolysis of sea water, the water molecules are broken down into hydrogen and oxygen gases. The hydrogen gas is collected at the cathode, while the oxygen gas is collected at the anode. This process separates the components of sea water based on their electrical charge.
pH can be measured using a pH meter, pH strips, or pH indicator solution. A pH meter provides a numerical value for pH, while pH strips or indicator solution change color based on the pH of the solution being tested.
A hot flame is a qualitative measurement, as it describes the subjective perception of the flame's temperature based on sensory experience rather than a precise numerical value.
Numerical relays are all microprocessor based, but there are relays that take the advantage of microprocessor technology and are not fully numerical. In other words, if a relay is fully based on processing the samples of input signals it is numerical relay.
To make electrolysis gel, combine water-based lubricant with a pinch of salt to increase conductivity. Mix well until the salt dissolves completely. The resulting gel can be used during electrolysis treatments to improve conductivity and comfort.
Yes, electrolysis has helped discover new elements, such as the isolation of sodium and potassium by Humphry Davy in the early 19th century. It is also commonly used in analytical chemistry to quantify the amount of a certain element in a compound.
No, they are both copper based. Copper and steel cause the problem.
The answer is Statistics
Stem and leaf plot
No, electrolysis is not typically used to separate DNA fragments. DNA separation techniques such as gel electrophoresis are more commonly used in molecular biology to separate DNA fragments based on size. Electrolysis is a process that uses an electric current to drive a chemical reaction.
Frank Stenger has written: 'Handbook of sinc numerical methods' -- subject(s): Differential equations, Numerical solutions, Galerkin methods 'Numerical methods based on Sinc and analytic functions' -- subject(s): Differential equations, Galerkin methods, Numerical solutions
Probability is a numerical measure. Occasionally, though, it is expressed in words such as very likely or not at all likely. But these phrases are (or should be) based on the fact that probability itself is a number.
Quantitative research is based on numerical measurements, such as statistics, percentages, and other numerical data. This approach involves collecting and analyzing data to draw conclusions and make predictions about a particular phenomenon. Quantitative research often utilizes statistical tools and methods to examine relationships between variables and test hypotheses.
Data tables can only display numerical data, as they organize information in rows and columns, often used for statistical analysis or numerical comparison. Additionally, certain types of graphs, like histograms or line charts, primarily represent numerical data visually, highlighting trends or distributions. While they may include categories, the core representation is based on numerical values.
In copper electrolysis, Faraday's law is used to calculate the amount of copper deposited on the cathode during electrolysis based on the current passing through the circuit and the duration of the electrolysis process. This law states that the amount of substance deposited on an electrode is directly proportional to the quantity of electricity passed through the solution. By knowing the molar mass of copper and the charge of an electron, the amount of copper deposited can be accurately determined using Faraday's law.