1-bromo-3-methylcyclohexane is the major monobrominated product formed when methylcyclohexane undergoes free radical bromination. This occurs because the bromine radical prefers to attack the tertiary carbon due to its greater stability compared to primary or secondary carbons.
A compound that contains the hydroxyl OH radical is called an alcohol. Alcohols are organic compounds that have a hydroxyl functional group attached to a carbon atom. Examples include ethanol (found in alcoholic beverages) and methanol (used as a solvent).
ortho-para in benzene is meaningless these positions are for monosubstituted benzene. Meta is positions 3 and 5. Ortho is position 2 and 6 with relation to already attached group, para is 4 (opposite) to attached group.
A RADICAL MAY BE A BASIC RADICAL HAVING POSITIVE CHARGE i.e., A CATION. EX: IN AMMONIUM CARBONATE AMMONIUM IS A BASIC RADICAL. ANSWERED BY VISRUTHA. THANQ. HAVE A NICE DAY.
There isn't one; that compound can't exist (technically, it might exist as a carbanion or carbocation or free radical, but not as a stable compound). Adding a hydrogen to the third carbon would make it 1-butanal; removing one from the second carbon would make it but-2-en-1-al.
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30
radical 3 or 6
3^3*radical(128) = 3^3*radical(2^7) = 3^3*radical(2^6*2) =3^3*2^3*radical(2) = 216*radical(2).
3
Radical (3x) = radical(x) * radical(3).
Radical 147 simplified is 7 radical 3. radical147= radical 49* radical 3 the square root of 49 is 7 therefore the answer is 7 radical 3
radical(48)/radical(3) = radical(48/3) = radical(16) = 4 Technically, radical(16) is +4 OR -4 but in such questions often only the principal root is required.
2 radical 30
Radical(27) can be simplified to 3*radical(3), so the correct answer is 6*radical(3).
4 radical 3 is about 6.92820323
30
9*radical(3)/2 = 4.5*radical(3) = 7.794 approx.