I guess SO3
The aqueous solution of H2SO4 is called sulfuric acid.
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
When sulfuric acid (H2SO4) dissolves in water, it dissociates into hydronium ions (H3O+) and sulfate ions (SO4^2-). These are the primary species present in the solution.
H2SO4 (aqueous), it exists at H+ and HSO4-
When aqueous H2SO4 and aqueous NaOH react by double replacement, they form water (H2O) and sodium sulfate (Na2SO4) as products. The reaction is H2SO4 + 2NaOH → 2H2O + Na2SO4.
The aqueous solution of H2SO4 is called sulfuric acid.
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
When sulfuric acid (H2SO4) dissolves in water, it dissociates into hydronium ions (H3O+) and sulfate ions (SO4^2-). These are the primary species present in the solution.
H2SO4 (aqueous), it exists at H+ and HSO4-
When aqueous H2SO4 and aqueous NaOH react by double replacement, they form water (H2O) and sodium sulfate (Na2SO4) as products. The reaction is H2SO4 + 2NaOH → 2H2O + Na2SO4.
To dilute the 3.5 M H2SO4 solution to 2 M, you need to add water. Use the formula M1V1 = M2V2, where M represents molarity and V represent volume. For this situation, you'll end up adding 75 ml of water to the initial 75 ml of 3.5 M H2SO4 solution to achieve a final 2 M concentration.
No, H2SO4 is an electrolyte, as it produces hydronium ions in aqueous solution.
This reaction is:NaCl + H2SO4 = NaHSO4 + HCl
The most common diprotic acid is sulphuric acid; H2SO4(aq) as this has 2 H+ to donate.
The balanced equation for the reaction between sulfuric acid (H2SO4) and calcium sulfide (CaS) in aqueous solution is: H2SO4(aq) + CaS(aq) → CaSO4(s) + H2S(g)
The formula for aqueous hydrogen sulfate is H2SO4.
Start with 1 dm^3 (1 Liter) of pure H2O. Molarity is defined as Mol/dm^3, so this is generally an easy way to go. Measure out 3 mol of H2SO4 -> First find the molar weight of Sulfuric acid, which is, according to Google: 98.079g/mol. So 3 mol * 98.079g/mol = 294.24 grams of H2SO4. Add that to 1 Liter of water, and you'll have an aqueous 3 Molar solution!