Carbon Dioxide.
H2CO3 <--> CO2 + H2O
NaCl + H2CO3
Nothing. NaHSO4 + NaCl ---> HCl + Na2SO4
Youwill getCO2 (g) + H2O (l) + NaCL(aq)don't forget to balance the equation!!!
Na2CO3 + 2 HCl = CO2 + H2O + 2 NaCl
Double replacement
NaCl + H2CO3
methyl orange
Nothing. NaHSO4 + NaCl ---> HCl + Na2SO4
Youwill getCO2 (g) + H2O (l) + NaCL(aq)don't forget to balance the equation!!!
Na2CO3 + 2 HCl = CO2 + H2O + 2 NaCl
Double replacement
NaCl doesn't react with KNO3.NaCl + AgNO3 = NaNO3 + AgCl(s)NaOH + HCl = NaCl + H2ONa2CO3 + 2 HCl = 2NaCl + CO2 + H2OBaCl2 + H2SO4 = BaSO4(s) + 2 HClCuSO4 and Zn(NO3)2 doesn't react.
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
solution containig (3.3)gm na2co3 .h2o in (15ml)
Balanced equation first, last and always! Na2CO3 + 2HCl - > 2NaCl + CO2 + H2O 2.5 g Na2CO3 ( 1 mole Na2CO3/105.99 g)(2 mole HCl/1 mole Na2CO3) 0.04717 moles HCl -------------------------Now, Molarity = moles of solute/liters of solution or, for our purposes liters of solution = moles of solute/Molarity Liters HCl = 0.04717 moles HCl/0.60 M HCl = 0.0786 liters (1000 milliliters/1 liter) = 78. 6 milliliters HCl solution needed
The chemical equation is:Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O
nothing happens..........