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  1. Thoroughly heat your crucible and allow it to cool on the clay triangle. Then weigh your crucible. This ensures that it is clean and dry.
  2. Obtain about 1 g of CuSO4·5H2O in your crucible and weigh it, recording the mass to the maximum available precision.
  3. Make a prediction about the amount of mass that will be lost when you heat the sample of copper (II) sulfate pentahydrate. Specifically, calculate the mass of the anhydrous salt and the mass of water that will be driven off. Show this to your instructor before proceeding.
  4. Once you have your instructor's approval, place the crucible containing the CuSO4·5H2O on the clay triangle.
  5. Light the bunsen burner and adjust for a hot flame.
  6. Heat the crucible as gently as possible with the burner by moving the burner under the crucible for a few seconds at a time. Note the release of any steam from the crucible.
  7. Remove the heat source and use a pair of lab spatulas to occasionally stir the copper sulfate. Carefully scrape all of it back into the crucible. Be careful not to do this while heating!
  8. Continue heating gently until the salt turns completely white. Be careful not to overheat! The heat can become so intense that the sulfate in the salt begins to break down. If this happens the salt will turn yellow and produce a sulfurous smell. It will also ruin your data since it will reduce the mass more than expected due to the decomposition of the salt.
  9. Stop heating when the salt has lost all traces of blue color. Allow the crucible and its contents to cool completely.
  10. Once the crucible is cool, find its mass. Then stir the copper(II) sulfate and heat the crucible and its contents again for a short time. Then allow it to cool and weigh it. If the mass is the same as the previous weighing, then the salt has been completely dehydrated. If not, repeat the heating/cooling/weighing process until two successive weighings have the same mass.
  11. Record the final mass of the anhydrous salt in you lab notebook and do the calculations to show that the molar ratio of water to anhydrous salt really is 5:1.
  12. Empty the anhydrous salt onto a large watch glass. Use the dropper to add a very little water to the anhydrous copper (II) sulfate. Describe what happens in your lab notebook. For your report think about what is happening at the molecular level when you add water. Draw a model.
  13. When you finished this part of the lab empty the re-hydrated CuSO4·5H2O into the beaker provided by your instructor for this purpose. Then begin Part II.
Part II

In this part of the lab you will repeat the same procedure performed for the salt of known formula with a salt for which you do not know the hydrate formula. The salt is magnesium sulfate (MgSO4). Your correct identification of the hydrate formula is worth 5 points on your lab report. To ensure better chances of getting the correct result you may want to consider doing at least two (and perhaps three) trials. For each trial use a minimum of 2 g. The magnesium sulfate is not nearly so hazardous as the copper (II) sulfate and a larger amount will help to reduce errors due to small lab balance inaccuracies. An additional challenge is that both the hydrate and anhydrous salt are white. Finally, unless you frequently stop heating to stir the crystals they will combine and harden, possibly trapping water inside.

By the way, magnesium sulfate is the chemical name for Epsom Salts. Epsom Salts were discovered by a farmer in Epsom, England. Every day his cows waded through water containing naturally high amounts of magnesium sulfate. He found that the cows showed evidence of diarrhea but also that the incidence of small wounds near their hooves was reduced. Epsom Salts are used as a laxative and in foot soaks and bath salts. It soothes tired muscles and can help to heal skin problems, including acne.

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What is the correct name for hydrate CuSO4.5H2O?

Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate


How many water molecules bound in copper sulfate?

The most common form is the pentahydrate.


How many grams of copper(II) sulfate pentahydrate would you need to measure in order to have 10.0 grams of anhydrous copper (II) sulfate?

To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.


What happens if Copper Sulphate penta-hydrate is heated?

When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.


Hydrated forms of copper sulfate?

The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.

Related Questions

What is the correct name for hydrate CuSO4.5H2O?

Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate


How many water molecules bound in copper sulfate?

The most common form is the pentahydrate.


Describe the appearance and odor of the liquid obtained by heating copper 11 sulfate pentahydrate?

When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.


What kind of chemical reaction do you get when you heat copper sulfate pentahydrate?

Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.


How many grams of copper(II) sulfate pentahydrate would you need to measure in order to have 10.0 grams of anhydrous copper (II) sulfate?

To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.


What happens if Copper Sulphate penta-hydrate is heated?

When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.


Hydrated forms of copper sulfate?

The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.


Is copper II sulfate pentahydrate sublime?

No, copper II sulfate pentahydrate does not sublime. Sublimation is the process of a substance transitioning directly from a solid to a gas without passing through the liquid phase, and copper II sulfate pentahydrate decomposes before it can sublime.


What colour does water change anhydrous copper sulfate?

When water is added to anhydrous copper sulfate, it forms copper (II) sulfate pentahydrate, a blue crystalline solid. So, the color change observed is from white (anhydrous) to blue (pentahydrate) when water is added.


What is the balanced equation when copper ll sulfate pentahydrate is heated?

The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.


How many molecules does copper-II sulfate pentahydrate have?

Each molecule of copper(II) sulfate pentahydrate contains one copper atom, one sulfur atom, four oxygen atoms, and five water molecules. So, one molecule of copper(II) sulfate pentahydrate contains a total of 11 atoms.


Is copper II sulfate pentahydrate an ionic compound?

Yes, copper (II) sulfate pentahydrate is an ionic compound. It is composed of positively charged copper ions (Cu^2+) and negatively charged sulfate ions (SO4^2-) held together by ionic bonds.