1. Iron and iron oxides are solids.
2. Carbon oxides are gases.
There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
Because C and Fe appear in uncombined, atomic form in this equation we can ignore them initially and just look at the Fe2O3 and CO2. There are an odd number of atoms of O in the Fe2O3 and a odd number in the CO2. If I just double the number of molecules of Fe2O3 going into the reaction then this will also double the number of atoms of oxygen, thereby making the number even(which is what I want, eh). Here's what I have so far:2 Fe2O3 + C -> Fe + CO2Because there are six oxygen atoms on the left there must be six on the right. Therefore there are three CO2 molecules:2 Fe2O3 + C -> Fe + 3 CO2Finally:Four Fe's going in means four must come out.Three C's coming out means three must go in.2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
Fe2O3 + 3CO -----> 2Fe + 3CO2
Fe2O3 (s) + 3CO (g) -----> 2Fe (s) + 3CO2 (g) This is just the balanced chemical equation. It says nothing about the actual method and reaction conditions for performing the reaction. The mixture would most likely need to be heated signficantly. Why worry about dealing with carbon monoxide, when simple carbon will do? Again, significant heating of the mixture is required. 2Fe2O3 (s) + 3C (s) -----> 4Fe (s) + 3CO2 (g)
There are several different possible reactions of Fe2O3 with CO, depending on temperature and ratio of reactants. The simplest is probably Fe2O3 + CO ==>2FeO + CO21.00 Kg x 1000 g/Kg x 1 mole Fe2O3/160 g = 6.25 moles Fe2O3 moles CO2 produced = 6.25 moles CO2 Volume CO2 at STP = 6.25 moles x 22.4 L/mole = 140 Liters
Fe2O3 (s) + 3 CO (g) 🡪 2 Fe (s) + 3 CO2 (g) Calculate the number of grams of CO that can react with 250 g of Fe2O3. Calculate the number of grams of Fe and the number of grams of CO2 formed when 250 grams of Fe2O3 reacts.
Because C and Fe appear in uncombined, atomic form in this equation we can ignore them initially and just look at the Fe2O3 and CO2. There are an odd number of atoms of O in the Fe2O3 and a odd number in the CO2. If I just double the number of molecules of Fe2O3 going into the reaction then this will also double the number of atoms of oxygen, thereby making the number even(which is what I want, eh). Here's what I have so far:2 Fe2O3 + C -> Fe + CO2Because there are six oxygen atoms on the left there must be six on the right. Therefore there are three CO2 molecules:2 Fe2O3 + C -> Fe + 3 CO2Finally:Four Fe's going in means four must come out.Three C's coming out means three must go in.2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
Fe2O3 + 3CO -----> 2Fe + 3CO2
Fe2O3 (s) + 3CO (g) -----> 2Fe (s) + 3CO2 (g) This is just the balanced chemical equation. It says nothing about the actual method and reaction conditions for performing the reaction. The mixture would most likely need to be heated signficantly. Why worry about dealing with carbon monoxide, when simple carbon will do? Again, significant heating of the mixture is required. 2Fe2O3 (s) + 3C (s) -----> 4Fe (s) + 3CO2 (g)
Fe2O3 + C --> Fe + CO2 balances it's 2 iron oxides, three carbons, 4 irons and 3 CO2s :)
iron(III) oxide Fe2O3 carbon dioxide CO2
Yes
Solids-Rocks,Wood,Plastics............... Liquids-Water Gases-CO2.O2..................................
Depict moles eg: Fe2O3(s) + 3CO(g)--> 2Fe(s) + 3CO2(g) 1 mole of Fe2O3 4 moles of CO 2 moles of Fe 3 moles of CO2
Yes, your CO2
6.02 ten to the power of 23