No reaction, because iron is a more active metal than copper. This means that copper cannot reduce iron from its salt.
When silver is immersed in copper sulphate solution, a redox reaction takes place where silver displaces copper from the copper sulphate solution. This results in the formation of silver sulphate and metallic copper deposits on the silver surface. Over time, the silver object may lose its shine due to the formation of copper deposits on its surface.
When a silver spoon is immersed in aqueous copper sulphate solution, a displacement reaction occurs. The silver spoon will react with the copper sulphate, displacing the copper ions and forming silver sulphate solution. Over time, the silver spoon will start to turn slightly reddish as a thin layer of copper is deposited on its surface.
The iron is more reactive than copper so when the iron nail is immersed in copper sulphate the iron takes sulphate ion from the copper sulphate and copper metal is deposited on top of the iron so that the nail will then look like a copper nail.The chemical reaction is called a replacement reaction, and is chemically represented as : CuSO4(compound in solution) + Fe(metal) ------>Cu(deposited metal) + FeSO4.
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
In a displacement reaction between iron and copper sulphate, iron, being more reactive than copper, will displace copper from copper sulphate solution. The chemical equation for this reaction is: Fe + CuSO4 -> FeSO4 + Cu. This reaction results in the formation of iron sulphate and copper metal.
Any reaction occur.
When silver is immersed in copper sulphate solution, a redox reaction takes place where silver displaces copper from the copper sulphate solution. This results in the formation of silver sulphate and metallic copper deposits on the silver surface. Over time, the silver object may lose its shine due to the formation of copper deposits on its surface.
No chemical reaction would be expected to occur when a copper wire is immersed in an iron sulfate solution: Copper is less active than iron in the electromotive series and therefore can not displace iron from iron compounds, and sulfate ions are not sufficiently strong oxidants to causecopper to dissolve in water.
When a silver spoon is immersed in aqueous copper sulphate solution, a displacement reaction occurs. The silver spoon will react with the copper sulphate, displacing the copper ions and forming silver sulphate solution. Over time, the silver spoon will start to turn slightly reddish as a thin layer of copper is deposited on its surface.
The iron is more reactive than copper so when the iron nail is immersed in copper sulphate the iron takes sulphate ion from the copper sulphate and copper metal is deposited on top of the iron so that the nail will then look like a copper nail.The chemical reaction is called a replacement reaction, and is chemically represented as : CuSO4(compound in solution) + Fe(metal) ------>Cu(deposited metal) + FeSO4.
as silver is less reactive than copper the silver when immersed will loose its electrons and the copper will displace it. i apologize if it is the wrong answer.... this is actually a guess :P
Not realy.........
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
In a displacement reaction between iron and copper sulphate, iron, being more reactive than copper, will displace copper from copper sulphate solution. The chemical equation for this reaction is: Fe + CuSO4 -> FeSO4 + Cu. This reaction results in the formation of iron sulphate and copper metal.
A displacement reaction occurs when a more reactive element displaces a less reactive element in a compound. In this case, iron is more reactive than copper and displaces it in the copper-sulphate solution to form iron sulphate and copper metal.
Because a displacement reaction has occured
The chemical reaction is:Fe + CuSO4 = FeSO4 + Cu