It is colorless
In an aqueous solution of K2SO4, the ions present are potassium (K+) and sulfate (SO4^2-) ions.
The PH is neutral people usually think its basic because KHSO4 is slightly basic (or they think both are neutral), both come from the sulfuric acid, but K2SO4 is neutral because SO4(2-) has no proton to share and can't act as an acid anymore in the solution.
Yes, an aqueous solution of K2SO4 would contain ions. K2SO4 dissociates into K+ and SO4^2- ions in water, as it is a salt that is soluble in water. These ions contribute to the solution's conductivity and reactivity.
The pH of K2SO4 is close to neutral, around 7. This is because K2SO4 is a salt that is fully dissociated in water, resulting in the formation of K+ and SO4^2- ions, which do not significantly affect the pH of the solution.
The van't Hoff factor for K2SO4 is 3. This is because K2SO4 dissociates into 2 K+ ions and 1 SO4^2- ion in solution, resulting in a total of 3 ions when it dissociates completely.
The volume is 1,635 L.
In an aqueous solution of K2SO4, the ions present are potassium (K+) and sulfate (SO4^2-) ions.
The PH is neutral people usually think its basic because KHSO4 is slightly basic (or they think both are neutral), both come from the sulfuric acid, but K2SO4 is neutral because SO4(2-) has no proton to share and can't act as an acid anymore in the solution.
Yes, an aqueous solution of K2SO4 would contain ions. K2SO4 dissociates into K+ and SO4^2- ions in water, as it is a salt that is soluble in water. These ions contribute to the solution's conductivity and reactivity.
The pH of K2SO4 is close to neutral, around 7. This is because K2SO4 is a salt that is fully dissociated in water, resulting in the formation of K+ and SO4^2- ions, which do not significantly affect the pH of the solution.
The van't Hoff factor for K2SO4 is 3. This is because K2SO4 dissociates into 2 K+ ions and 1 SO4^2- ion in solution, resulting in a total of 3 ions when it dissociates completely.
Barium chloride solution: Ba2+ and Cl-. Potassium sulfate: K+ and (SO4)2-.
No, K2SO4 (potassium sulfate) is a strong electrolyte. When dissolved in water, it dissociates completely into ions, leading to a high conductivity solution.
To calculate the grams of K2SO4 needed to prepare the solution, use the formula: (molarity) x (volume in liters) x (molar mass of K2SO4). First, calculate the moles of K2SO4 needed: 0.0510 mol/L x 4.00 L = 0.204 mol. Then, find the molar mass of K2SO4: 2*(39.10 g/mol) + 1*(32.07 g/mol) + 4*(16.00 g/mol) = 174.26 g/mol. Finally, multiply the moles by the molar mass: 0.204 mol x 174.26 g/mol ≈ 35.5 grams of K2SO4 are needed.
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is: BaCl2 + K2SO4 -> BaSO4 + 2KCl
When sulfuric acid (H2SO4) is added to a potassium chromate (K2CrO4) solution, the orange-yellow color of the chromate ions will change to red, due to the formation of chromium ions in the +6 oxidation state (CrO4^2- --> Cr2O7^2-).
The balanced equation for BaCl2 + K2SO4 -> BaSO4 + 2KCl is BaCl2 + K2SO4 -> BaSO4 + 2KCl.