Hydrogen : 1.00794
Oxygen : 15.9994
The atomic weight of oxygen is 15.9994, and the atomic weight of hydrogen is 1.00794. Therefore, an oxygen atom weights about 15.87 (almost 16) times the weight of a hydrogen atom. So if you have the same number of atoms of each, the weight of the oxygen will be about 16 times the weight of the hydrogen, which is what you have (64g is about 16 times 4g). Therefore, H2O and HO2 are impossible, but HO is possible. (I am not the original writer)
the answer would be a 2:1 ratio. So H2O1 and that will come out to H2O.
Calculations
64g O x 1mol O / 16 g O = 4 mol O
8g H x 1mol H / 1.01 g H = 7.9 (round up) = 8 mol H
4/4 = 1
8/4 = 2
(dont get mixed up the 8 is the hydrogen and the 4 is the oxygen so the 2 goes with the hydrogen and the 1 goes to the oxygen to make it H2O1)
2:1 ratio
Thats how u get the empirical formula.
N2o5
64
The gram-atomic mass of sulphur is 32 and that of oxygen is 16, to two significant digits. Therefore, the mass of oxygen with the same number of atoms as 64 grams of sulphur can be found from the proportion m/64 = 16/32, or m = 32 grams.
45 g water are obtained.
BeO has 64 % oxygen.
Cocaine is C17H21NO4 and has a molar mass of 303.353 g/mole. Mass of oxygen in cocaine is 4x16 = 64. So, % oxygen by mass is 64/303.353 (x100) = 21% (to 2 sig. figs)
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From the formula of the compound, each molecular unit contains 2 copper atoms, 4 oxygen atoms, one carbon atom, and 2 hydrogen atoms. Multiplying each of these by its corresponding atomic mass gives 127 atomic mass units ("amu") of copper, 64 amu of oxygen, 12 amu of carbon, and 2 amu of hydrogen. Copper is clearly present in the largest percent by mass.
64
similar to separating the oxygen and hydrogen in water. When the battery fully charged it is made up of 64% water and 36% sulfuric acid and when the battery is in "charging" state by the alternator or charging source the electricity basically separates the water molecules (hydrogen from oxygen) giving of the hydrogen as bubbles.....sKD
The gram-atomic mass of sulphur is 32 and that of oxygen is 16, to two significant digits. Therefore, the mass of oxygen with the same number of atoms as 64 grams of sulphur can be found from the proportion m/64 = 16/32, or m = 32 grams.
50% of 64 g compound XX = 32, so 32 g S = 1.0 mole S 50% of 64 g compound XX = 32, so 32 g O2 = 1.0 mole O2 or =2.0 mole O atoms Thus it is SO2
H2SO4---------2 H (hydrogen) = 2.016 grams1 S (sulfur) = 32.07 grams4 O (oxygen) = 64 grams---------------------------------------Add.= 98.086 grams===========
1 cup contains 8 ounces, so 64 ounces contains 8 cups.
45 g water are obtained.
The number of moles in exactly 64 grams of oxygen (O2) is two.
BeO has 64 % oxygen.
97% is the normal oxygen saturation.