0
Hydrogen : 1.00794
Oxygen : 15.9994
The atomic weight of oxygen is 15.9994, and the atomic weight of hydrogen is 1.00794. Therefore, an oxygen atom weights about 15.87 (almost 16) times the weight of a hydrogen atom. So if you have the same number of atoms of each, the weight of the oxygen will be about 16 times the weight of the hydrogen, which is what you have (64g is about 16 times 4g). Therefore, H2O and HO2 are impossible, but HO is possible. (I am not the original writer)
What else can I help you with?
What is the percent of O in H2SO4?
In sulfuric acid (H2SO4), there are two oxygen atoms in the formula. To find the percentage of oxygen, you calculate the molar mass of oxygen (O) in the compound and divide it by the molar mass of the entire compound, then multiply by 100 to get the percentage. In this case, the percentage of oxygen in sulfuric acid is 48.65%.
The mass of oxygen which contains the same number of atoms as those present in 64 grams of sulfur is?
The gram-atomic mass of sulphur is 32 and that of oxygen is 16, to two significant digits. Therefore, the mass of oxygen with the same number of atoms as 64 grams of sulphur can be found from the proportion m/64 = 16/32, or m = 32 grams.
What is the mass of oxygen in 250 g of sulfuric acid H2SO4?
To find the mass of oxygen in sulfuric acid (H2SO4), we first need to calculate the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. The molar mass of oxygen in H2SO4 is 4 * 16 = 64 g/mol. To find the mass of oxygen in 250 g of H2SO4, we can use the proportion: (64 g / 98.08 g) * 250 g = 161.3 g of oxygen.
What is the percentage composition of C14H20N2SO4?
Here we go: C14H20N2SO4 has 14 carbons, 20 hydrogens, 2 nitrogens, 1 sulfur, and 4 oxygens. (That's penicillin, by the way.) The molar mass is the total mass of all the atoms, which works out to be 312g/mol. Now, just get part divided by total for each: Carbon: 12x14=168, 168/312=0.54=54% Hydrogen: 1x20=20, 20/312=0.06=6% Nitrogen: 14x2=28, 28/312=0.09=9% Sulfur: 32x1=32, 32/312=0.1=10% Oxygen: 16x4=64, 64/312=0.21=21% *(just make sure your percents all add up to 100!)
How many moles are in 64 grams of oxygen gas?
four moles. Approximately. Oxygen has a molecular weight of 16.0 grams per mole so 64 grams divided by 16.0 grams per mole is four moles.
A Sample of a compound contains 64 g of copper and 16 g of oxygen what is the ratio of mass to copper of oxygen?
The ratio of mass of copper to oxygen in the sample is 4:1. This is determined by dividing the mass of copper (64 g) by the mass of oxygen (16 g).
In the compound Cu2OH2CO3 which element is present with the largest percent by mass?
From the formula of the compound, each molecular unit contains 2 copper atoms, 4 oxygen atoms, one carbon atom, and 2 hydrogen atoms. Multiplying each of these by its corresponding atomic mass gives 127 atomic mass units ("amu") of copper, 64 amu of oxygen, 12 amu of carbon, and 2 amu of hydrogen. Copper is clearly present in the largest percent by mass.
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of ovygen?
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
How do batteries to produce hydrogen gas?
similar to separating the oxygen and hydrogen in water. When the battery fully charged it is made up of 64% water and 36% sulfuric acid and when the battery is in "charging" state by the alternator or charging source the electricity basically separates the water molecules (hydrogen from oxygen) giving of the hydrogen as bubbles.....sKD
What is the empirical formula of a compound whose composition by mass is 50 percent sulfur and 50 percent oxygen?
50% of 64 g compound XX = 32, so 32 g S = 1.0 mole S 50% of 64 g compound XX = 32, so 32 g O2 = 1.0 mole O2 or =2.0 mole O atoms Thus it is SO2
What is the percent of O in H2SO4?
In sulfuric acid (H2SO4), there are two oxygen atoms in the formula. To find the percentage of oxygen, you calculate the molar mass of oxygen (O) in the compound and divide it by the molar mass of the entire compound, then multiply by 100 to get the percentage. In this case, the percentage of oxygen in sulfuric acid is 48.65%.
What is mass of one mole of sulfuric acid?
H2SO4---------2 H (hydrogen) = 2.016 grams1 S (sulfur) = 32.07 grams4 O (oxygen) = 64 grams---------------------------------------Add.= 98.086 grams===========
Which best represents the number of moles in exactly 64 grams of oxygen (O2)?
The number of moles in exactly 64 grams of oxygen (O2) is two.
The mass of oxygen which contains the same number of atoms as those present in 64 grams of sulfur is?
The gram-atomic mass of sulphur is 32 and that of oxygen is 16, to two significant digits. Therefore, the mass of oxygen with the same number of atoms as 64 grams of sulphur can be found from the proportion m/64 = 16/32, or m = 32 grams.
How much water wold form if 14.8 grams of hydrogen reacted with 34.8 grams of oxygen?
45 g water are obtained.
What is the formula of the second compound if two oxides of a metal contain 27.6 percent and 30 percent of oxygen respectively and if the formula of the first compound is M3O4?
Formula of first oxide = M3O4 let mass of the metal be == x percentage of metal in M3O4 = (3x/ 3x+64) *100 but % age = (100-27.6) = 72.4 % so, (3x/ 3x+64)*100 = 72.4 or x = 56. in 2nd oxide, oxygen = 30%....so metal = 70% so, ratio :-- M : O 70/56 : 30/16 1.25 : 1.875 2 : 3 so, 2nd oxide = M2O3
What is the mass of oxygen in 250 g of sulfuric acid H2SO4?
To find the mass of oxygen in sulfuric acid (H2SO4), we first need to calculate the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. The molar mass of oxygen in H2SO4 is 4 * 16 = 64 g/mol. To find the mass of oxygen in 250 g of H2SO4, we can use the proportion: (64 g / 98.08 g) * 250 g = 161.3 g of oxygen.
