CHNOP(S), Carbon, Hydrogen, Oxygen, Phosphorus, and sometimes Sulfur. These are the most common elements in living organisms.
Al-h , c-h, n-h, o-h
ammonia have nitrogen atoms. but it doesn't contain C.
Isocyanate is a compound containing O, C, H, and N.
The bond stretching frequency increases with increasing bond strength. Therefore, the order of increasing bond stretching frequency is: F-H < O-H < N-H < C-H.
Ammonia contains N and H. It contains 3 H atoms.
Some amino acids contain phosphorus, and all nucleotides contain phosphorus.
Hypoallergenic
Al-h , c-h, n-h, o-h
ammonia have nitrogen atoms. but it doesn't contain C.
Isocyanate is a compound containing O, C, H, and N.
In order to be a group with respect to addition, the integers must satisfy the following axioms: 1) Closure under addition 2) Associativity of addition 3) Contains the additive identity 4) Contains the additive inverses 1) The integers are closed under addition since the sum of any two integers is an integer. 2) The integers are associative with respect to addition since (a+b)+c = a+(b+c) for any integers a, b, and c. 3) The integer 0 is the additive identity since z+0 = 0+z = z for any integer z. 4) Each integer n has an additive inverse, namely -n since n+(-n) = -n+n = 0.
The bond stretching frequency increases with increasing bond strength. Therefore, the order of increasing bond stretching frequency is: F-H < O-H < N-H < C-H.
To balance the reaction Ni + C₄H₈N₂O₂ → Ni(C₄H₈N₂O₂)₂, the coefficients would be 1 for Ni and 2 for C₄H₈N₂O₂. This results in the balanced equation: 1 Ni + 2 C₄H₈N₂O₂ → 1 Ni(C₄H₈N₂O₂)₂.
Ammonia contains N and H. It contains 3 H atoms.
Caffeine has the formula C₈H₁₀N₄O₂ so it contains 4 elements: carbon, hydrogen, nitrogen and oxygen.
The conjugate acid of the Brønsted-Lowry base C₄H₄N (which is pyridine) is formed by adding a proton (H⁺) to the base, resulting in C₄H₅N⁺. If you consider other forms of C₄H₄N, like an aniline or other amines, the conjugate acids would similarly involve adding a proton to form C₄H₅N⁺ or C₄H₄NH₃⁺, depending on the specific structure of the base.
ITS EASY...TRY THIS OUT..TRAPEZOIDAL METHOD#include#include#includefloat valcal(float x){return (x*x*x);}int main(){float a,b,h,c,I;int n,i;printf("THE TRAPEZOIDAL RULE:\n");printf("---------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;i=b){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));I=I+(2*valcal(c));//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/2);printf("\n\n\n");system("pause");}SIMPSON'S 1/3RD METHOD#include#include#includefloat valcal(float x){return (1/(1+x*x));}int main(){float a,b,h,c,I;int n,i;printf("THE SIMPSON'S ONE-THIRD RULE:\n");printf("------------------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;ib){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));if(i%2==0)I=I+(2*valcal(c));elseI=I+4*valcal(c);//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/3);printf("\n\n\n");system("pause");}NEED MORE HELP...MAIL ME YOUR PROB... SEE YA