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What is the pH of 15 mL of 0.0045 M HNO3?
pH = - log10 [H+], where [H+] is the molar concentration of hydrogen ions. HNO3 is a strong acid and dissociates completely in water so a 5 M solution of HNO3 would have a concentration of hydrogen ions of 5M also. So, pH = -log10[5] = -0.699 which indicates an extremely strong acid.
How many milliliters of a stock solution of 11.1 m hno3 would be needed to prepare 0.500 l of 0.500 m hno3?
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
What is the concentration of HNO3 in a solution with pH3.4?
The concentration of HNO3 in a solution with pH 3.4 is approximately 3.98 x 10^-4 M. This is calculated using the formula pH = -log[H+], where [H+] is the hydrogen ion concentration in mol/L. For nitric acid (HNO3), one mole of HNO3 produces one mole of H+ in solution.
A 3.0-milliliter sample of hno3 solution is exactly neutralized by 6.0 milliliters of 0.50 m koh what is the molarity of the hno3 sample?
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
What is the pH of a 0.6 M HNO3 solution?
The pH of a 0.6 M HNO3 solution is approximately 0.23. This is because nitric acid is a strong acid that completely ionizes in solution, resulting in a high concentration of H+ ions that lower the pH.
What is the pH of 15 mL of 0.0045 M HNO3?
pH = - log10 [H+], where [H+] is the molar concentration of hydrogen ions. HNO3 is a strong acid and dissociates completely in water so a 5 M solution of HNO3 would have a concentration of hydrogen ions of 5M also. So, pH = -log10[5] = -0.699 which indicates an extremely strong acid.
How many moles of hno3 are needed to prepare 5.0 of a 2.0 m solution of hno3?
10
What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
What is the molarity of HNO3 if 20.0 ml of the solution is needed to exactly neutralize 10.0 ml of a 1.67 M NaOH solution?
First write down the BALANCED reaction eq'n. HNO3 + NaOH = NaNO3 + H2O Note the molar ratios are all 1:1 :: 1:1 Next calculate the moles of NaOH ml Mol(NaOH) = 1.67 moles dm(-3) X 10 ml / 1000 NB THe 1000 is required to convert ml to dm^(3) , and then cancel down Hence mol(NaOH) = 0.0167 By '1:1' equivalence above , we need 0.0167 moles(HNO3( Hence 0.0167 = [Molarity/conc'n] X 20 ml / 1000 Algebraically rearrange. molarity/conc'n = 0.0167 x 1000 / 20 molarity = 0.835 Mol dm^(-3) or = 0.835 M .
What is the mean average of 6 15 and m?
The average of 6, 15 and m is (6 + 15 + m) / 3 = (21 + m)/3 = 7 + m/3
How many milliliters of a stock solution of 11.1 m hno3 would be needed to prepare 0.500 l of 0.500 m hno3?
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
What is the concentration of HNO3 in a solution with pH3.4?
The concentration of HNO3 in a solution with pH 3.4 is approximately 3.98 x 10^-4 M. This is calculated using the formula pH = -log[H+], where [H+] is the hydrogen ion concentration in mol/L. For nitric acid (HNO3), one mole of HNO3 produces one mole of H+ in solution.
What does 15 F of M mean?
if the question were 15 M of F then answer is 15 Minutes of Fame which was a quote from Andy Warhol
What does m2 - 8m 15 equal?
If you mean m^2 -8m +15 then it equals (m -3)(m -5) when factored
A 3.0-milliliter sample of hno3 solution is exactly neutralized by 6.0 milliliters of 0.50 m koh what is the molarity of the hno3 sample?
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
What is the pH of a 0.6 M HNO3 solution?
The pH of a 0.6 M HNO3 solution is approximately 0.23. This is because nitric acid is a strong acid that completely ionizes in solution, resulting in a high concentration of H+ ions that lower the pH.
What is the ratio in simplest form of 15 m 18 m?
I am assuming that you mean 15 meters by 18 meters. 15:18 = 5:6
