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What elements are found in magnesium bromide?
Magnesium (Mg) and Bromine (Br) - Magnesium Bromide - MgBr2
What is the oxidation number in magnesium bromide?
In magnesium bromide (MgBr2), magnesium has an oxidation number of +2 and each bromine atom has an oxidation number of -1. This is because magnesium typically forms 2+ cations, while bromine forms 1- anions.
What would be the most probable formula unit for a compound made of the elements Mg and Br?
The compound made of magnesium (Mg) and bromine (Br) would most likely have the formula MgBr2, where magnesium has a +2 charge and bromine has a -1 charge, resulting in a 1:2 ratio of magnesium to bromine atoms.
What is the chemical oxidation number for magnesium and bromine?
The chemical oxidation number for magnesium is +2 because it typically forms 2+ cations by losing two electrons. For bromine, the oxidation number can vary depending on the compound, but it commonly occurs as -1 in ionic compounds, like in magnesium bromide (MgBr2).
Is magnesium and bromine ionic?
YES!!!! Magnesium ionkses to form the magnesium cation . The two electrons ionised go to a bromine molecule (Br2) , and under electron affinity one electron combines with one bromine atom to for the bromide anion. Iomisation Mg(s) = Mg^(2+)(aq) + 2e^(-) Br2(l) + 2e^(-) = 2Br^(-) Adding Mg(s) + Br2(l) = MgBr2(s)
What does 1 magnesium atom and 2 bromine atoms make?
if you poop out fusions its correct
What is the name of 1 magnesium 2 bromine?
The compound consisting of one magnesium atom and two bromine atoms is called magnesium bromide. Its chemical formula is MgBr₂. Magnesium bromide is an ionic compound formed from magnesium, which has a +2 charge, and bromine, which has a -1 charge.
What elements are in magnesium bromide?
There are two elements in magnesium bromide viz., Magnesium and bromine.
What elements are found in magnesium bromide?
Magnesium (Mg) and Bromine (Br) - Magnesium Bromide - MgBr2
What is the oxidation number in magnesium bromide?
In magnesium bromide (MgBr2), magnesium has an oxidation number of +2 and each bromine atom has an oxidation number of -1. This is because magnesium typically forms 2+ cations, while bromine forms 1- anions.
What would be the most probable formula unit for a compound made of the elements Mg and Br?
The compound made of magnesium (Mg) and bromine (Br) would most likely have the formula MgBr2, where magnesium has a +2 charge and bromine has a -1 charge, resulting in a 1:2 ratio of magnesium to bromine atoms.
How many magnesium atoms would be needed to react with one bromine molecule?
Two magnesium atoms would be needed to react with one bromine molecule. Magnesium has a +2 oxidation state, while bromine has a -1 oxidation state. This means that two magnesium atoms are needed to balance the charges when reacting with one bromine molecule.
What is the ratio of mgbr2?
The ratio of magnesium bromide (MgBr₂) consists of one magnesium (Mg) atom to two bromine (Br) atoms. This means that for every one magnesium atom, there are two bromine atoms, resulting in a 1:2 ratio. In the compound, the subscript '2' indicates that there are two bromine atoms for each magnesium atom.
What does the two mean out of magnesium bromine 2?
The chemical formula of magnesium bromide is MgBr2; 2 is the number of bromine atoms in the molecule.
What is the empirical formula for 13 percent magnesium and 87 percent bromine?
The empirical formula for a compound containing 13% magnesium and 87% bromine is MgBr2. This is because the ratio of magnesium to bromine atoms in the compound is 1:2, which corresponds to the formula MgBr2.
What is the chemical oxidation number for magnesium and bromine?
The chemical oxidation number for magnesium is +2 because it typically forms 2+ cations by losing two electrons. For bromine, the oxidation number can vary depending on the compound, but it commonly occurs as -1 in ionic compounds, like in magnesium bromide (MgBr2).
Is MgBr2 a compound?
YES!!!! It is an ionic combination of magnesium with bromine. 1 magnesium atom combines ionically with two 2 atoms of bromine. Mg(s) + Br2(l) = Mg^(2+) aq + 2Br^(-)aq = MgBr2(s)
