NaH is a strong base, containing the H- ion. It will react to abstract the weakly acidic proton on the CH3OH to give the following reaction:
NaH + CH3OH --> Na (OCH3) + H2
The reaction between NaH and CH3OH produces sodium methoxide (NaOCH3) and hydrogen gas (H2). This reaction involves the displacement of hydrogen from methanol by the stronger base, sodium hydride. The balanced chemical equation is: 2 NaH + 2 CH3OH → 2 NaOCH3 + 2 H2.
2CH3OH + 3O2 --> 2CO2 + 4H2O
The products are water and carbon dioxide.
NaNH2 + CH3OH --> NH3 + CH3O- + Na+
Yields CH3NH3 + OH
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
Chloroform and methanol can react to form methyl chloroformate and hydrogen chloride in the presence of a base catalyst. The reaction equation is: CHCl3 + CH3OH → CH3OCOCl + HCl
The balanced equation for the reaction between sodium and hydrogen gas to form sodium hydride is: 2 Na + H2 -> 2 NaH
CH3OH is a weak acid, known as methanol. It can donate a proton in a chemical reaction, making it an acidic compound.
The balanced equation for the reaction is CO(g) + 2H2(g) → CH3OH(g). According to the stoichiometry of the reaction, 1 mol of CO reacts with 2 mol of H2 to produce 1 mol of CH3OH. Therefore, the calculated volume of the reactants and products would depend on the specific conditions of the reaction, such as temperature, pressure, and the volume of each gas at the beginning of the reaction.
The reaction of C13H10 with CH3OH would likely result in a substitution reaction, where CH3OH replaces one of the hydrogen atoms in C13H10. The specific product would depend on the reaction conditions and the specific mechanism of the reaction.
Chloroform and methanol can react to form methyl chloroformate and hydrogen chloride in the presence of a base catalyst. The reaction equation is: CHCl3 + CH3OH → CH3OCOCl + HCl
The most common reaction is:CO + 2 H2 = CH3OH
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
CuO + CH3OH --> HCHO + Cu + H2O
Copper (Cu) has a greater boiling point than methanol (CH3OH) because copper is a metal with strong metallic bonding that requires more energy to break compared to the weaker intermolecular forces (hydrogen bonding) present in methanol. The stronger bonds in copper result in a higher boiling point.
No CH3OH is a covalent compound becauseAn Ionic bond is formed between metals and nonmetalAs there are no metals in this compound so it cant be an ionic bond
To calculate the mass of 9.32x10^24 molecules of methanol (CH3OH), you can first find the molar mass of CH3OH, which is approximately 32 g/mol. Then, you can convert the number of molecules to moles and finally to grams. The calculation would be (9.32x10^24 molecules) / (6.022x10^23 molecules/mol) * (32 g/mol) = 497 grams.
CH3OH is molecular.
To find the mass of 9.03 x 10^24 molecules of methanol (CH3OH), we first calculate the molar mass of CH3OH: (1 x 12.01 g/mol) + (4 x 1.01 g/mol) + (1 x 16.00 g/mol) = 32.04 g/mol Then we can convert the number of molecules to moles and finally to grams: 9.03 x 10^24 molecules * (1 mol / 6.022 x 10^23 molecules) * 32.04 g/mol ≈ 482 g
Ch3oh
Methanol is CH3OH while ethanol is C2H5OH. The difference is CH2.