NaH is a strong base, containing the H- ion. It will react to abstract the weakly acidic proton on the CH3OH to give the following reaction:
NaH + CH3OH --> Na (OCH3) + H2
2CH3OH + 3O2 --> 2CO2 + 4H2O
The products are water and carbon dioxide.
NaNH2 + CH3OH --> NH3 + CH3O- + Na+
Yields CH3NH3 + OH
chcl3+CH3OH
No CH3OH is a covalent compound becauseAn Ionic bond is formed between metals and nonmetalAs there are no metals in this compound so it cant be an ionic bond
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
192.678 grams CH3OH
The reaction of C13H10 with CH3OH would likely result in a substitution reaction, where CH3OH replaces one of the hydrogen atoms in C13H10. The specific product would depend on the reaction conditions and the specific mechanism of the reaction.
chcl3+CH3OH
The most common reaction is:CO + 2 H2 = CH3OH
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
CuO + CH3OH --> HCHO + Cu + H2O
Cu has a lower boiling point than CH3OH because its particles are less polar. the CH3OH molecules have to have more kinetic energy to break the bonds between them and the surrounding molecules.
No CH3OH is a covalent compound becauseAn Ionic bond is formed between metals and nonmetalAs there are no metals in this compound so it cant be an ionic bond
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
CH3OH is molecular.
9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH
Ch3oh
Methanol is CH3OH while ethanol is C2H5OH. The difference is CH2.