I think it depends to the strucure of your C13H10... It depends if its ring shape or double bonded or triple bonded...
The most common reaction is:CO + 2 H2 = CH3OH
No, CH3OH is not an element. It is a compound with the chemical formula CH3OH, which represents methanol, a type of alcohol.
When hydrogen is added to carbon monoxide (CO), it can react to form methanol (CH3OH) through a process known as hydrogenation. This reaction typically requires a catalyst and occurs under specific conditions of temperature and pressure. The overall reaction can be represented as CO + 2H2 → CH3OH. Methanol is an important chemical used as a fuel and in the production of various chemicals.
A chemical substance formed as a result of a chemical reaction is called a product. Products can be either the desired end product of the reaction or byproducts that are formed during the reaction.
An insoluble product in a chemical reaction is a precipitate. It does not dissolve in the solvent in which the reaction was conducted.
C13H10
Chloroform and methanol can react to form methyl chloroformate and hydrogen chloride in the presence of a base catalyst. The reaction equation is: CHCl3 + CH3OH → CH3OCOCl + HCl
NaH is a strong base, containing the H- ion. It will react to abstract the weakly acidic proton on the CH3OH to give the following reaction:NaH + CH3OH --> Na (OCH3) + H2
The balanced equation for the reaction is CO(g) + 2H2(g) → CH3OH(g). According to the stoichiometry of the reaction, 1 mol of CO reacts with 2 mol of H2 to produce 1 mol of CH3OH. Therefore, the calculated volume of the reactants and products would depend on the specific conditions of the reaction, such as temperature, pressure, and the volume of each gas at the beginning of the reaction.
The most common reaction is:CO + 2 H2 = CH3OH
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
When methanol (CH3OH) reacts with sulfuric acid (H2SO4), it forms dimethyl ether (CH3OCH3) and water (H2O) as products. This reaction is known as the dehydration of methanol.
NONE of them. CH3OH is an organic alcohol ( Methanol). However, in suitable circumstances it will react with an acid to form as ester.
Methanol and water do not react they just form a very stable solution.
CH3OH is neither an acid or a base, nor is it a salt. It is an alcohol, and even though it ends in OH, it does not dissociate in water. You can tell an alcohol by the hydrocarbon group CH3, making it an organic compound.
The reaction between CH3CH2MgBr (ethylmagnesium bromide) and methanol results in the formation of ethanol and magnesium bromide. The balanced equation for this reaction is: CH3CH2MgBr + CH3OH -> CH3CH2OH + MgBr2
How can the product of a reaction be maximized?