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It depends on the amount of each reactant. HCl and H2SO4 are both strong acids, but H2SO4is only strong for the first H and is weak in the second. As soon as the Na2SO4 is put in the water it disassociates into Na+ and SO4-2, like wise the HCl becomes H+ and Cl-. Almost all the H+ released by the HCl will become attached to the SO4-2 ion until all the SO4-2 ions become HSO4-1. Any excess H+ ion provided by the HCl will react with the water to become H3O+1 or hyronium.

I found this equilibrium constant from an abstract from sceintific journal.

Journal of Solution Chemistry V23 #1 p75-80

Ka2 = .0184 = [H3O+1][SO4-2]/[HSO4-1]

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