It depends on the amount of each reactant. HCl and H2SO4 are both strong acids, but H2SO4is only strong for the first H and is weak in the second. As soon as the Na2SO4 is put in the water it disassociates into Na+ and SO4-2, like wise the HCl becomes H+ and Cl-. Almost all the H+ released by the HCl will become attached to the SO4-2 ion until all the SO4-2 ions become HSO4-1. Any excess H+ ion provided by the HCl will react with the water to become H3O+1 or hyronium.
I found this equilibrium constant from an abstract from sceintific journal.
Journal of Solution Chemistry V23 #1 p75-80
Ka2 = .0184 = [H3O+1][SO4-2]/[HSO4-1]
The reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) will yield potassium sulfate (K2SO4) and water (H2O) as the products. This is a neutralization reaction where an acid reacts with a base to form a salt and water.
Butanol and methanol will react in the presence of heat and concentrated H2SO4 to yield methyl butanoate. This reaction is an esterification reaction, where an alcohol and a carboxylic acid combine to form an ester.
When methanol (CH3OH) reacts with sulfuric acid (H2SO4), it forms dimethyl ether (CH3OCH3) and water (H2O) as products. This reaction is known as the dehydration of methanol.
Moles NaNO3 = 156 g / 84.9965 g/mol = 1.84 we would get 1.84 moles of NaNO2 => 1.84 mol x 68.9965 g/mol = 127 g % = 112 x 100 / 127 = 88.2
Sodium nitrite (NaNO2) is not a basic compound. It is a salt that is soluble in water and it can act as both an oxidizing agent and a reducing agent in chemical reactions.
k2so4+hno2
Formula: NaNO2
The reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) will yield potassium sulfate (K2SO4) and water (H2O) as the products. This is a neutralization reaction where an acid reacts with a base to form a salt and water.
Butanol and methanol will react in the presence of heat and concentrated H2SO4 to yield methyl butanoate. This reaction is an esterification reaction, where an alcohol and a carboxylic acid combine to form an ester.
When methanol (CH3OH) reacts with sulfuric acid (H2SO4), it forms dimethyl ether (CH3OCH3) and water (H2O) as products. This reaction is known as the dehydration of methanol.
NaNO2
The balanced chemical equation for the decomposition of sodium nitrate (NaNO3) into sodium nitrite (NaNO2) and oxygen (O2) is: 2 NaNO3 --> 2 NaNO2 + O2
Moles NaNO3 = 156 g / 84.9965 g/mol = 1.84 we would get 1.84 moles of NaNO2 => 1.84 mol x 68.9965 g/mol = 127 g % = 112 x 100 / 127 = 88.2
sodium (Na), nitrogen (N), and two oxygenatoms (O)
Sodium nitrite (NaNO2) is not a basic compound. It is a salt that is soluble in water and it can act as both an oxidizing agent and a reducing agent in chemical reactions.
NaNO2 and KCl
MgCl2 + H2SO4 ---> MgSO4 + 2HCl yield magnesium sulfate plus hydrogen chloride(gaz)