NiCl2 + 2 NaBr-----------NiBr2 + 2 NaCl
C4H9Br+NaOH > NaBr + C4H10O
This equation is 2 Na + Br2 -> 2 NaBr.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
No, NaBr is a neutral salt.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Get moles NaBr 1.5 M NaBr = moles NaBr/0.075 Liters = 0.1125 moles NaBr (102.89 grams/1 mole NaBr) = 11.575 grams NaBr ( call it 12 grams ) ----------------------------------------------------
2 Na + Br2 --> 2 NaBr
C4H9Br+NaOH > NaBr + C4H10O
This equation is 2 Na + Br2 -> 2 NaBr.
the equation is, NaBr + AgNO3 = AgBr(pale yellow ppts) + NaNO3(aq.)
Any reaction occur between these compounds. For preparation:NaOH + HBr = NaBr + H2OKOH + HNO3 = KNO3 + H2OCaCl2 + H2S + CaS + 2 HCl
We know that the alkali metal sodium (Na) will form an ionic bond with the halogen bromine (Br) to create sodium bromide (NaBr). The equation looks like this: Na + Br => NaBr
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
Nickel chloride
NaBr would be a formula unit as all sodium (Na) compounds are ionic.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
Sodium bromide (NaBr) has a weight of 102.89 grams per mole. Determining the mass of NaBr in a mixture can be calculated if the constituent weights of all the others are known. The total masses of the knows can be subtracted by the overall weight to isolate the mass of NaBr.
No, NaBr is a neutral salt.