NiCl2 + 2 NaBr-----------NiBr2 + 2 NaCl
The molecular equation is NaBr (s) + Ca(NO3)2 (aq) -> CaBr2 (s) + 2 NaNO3 (aq). The ionic equation is 2Na+ (aq) + 2NO3- (aq) + Ca2+ (aq) + 2Br- (aq) -> CaBr2 (s) + 2Na+ (aq) + 2NO3- (aq).
The balanced equation for the formation of sodium bromide from sodium and bromine is: 2 Na + Br2 → 2 NaBr
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
The balanced equation for sodium bromide (NaBr) and silver nitrate (AgNO3) is: 2NaBr + AgNO3 → 2NaNO3 + AgBr.
The hydrolysis reaction of C4H9Br with NaOH can be represented as follows: C4H9Br + NaOH -> C4H9OH + NaBr This reaction involves the substitution of the bromine atom in C4H9Br with the hydroxide ion from NaOH, resulting in the formation of C4H9OH (butanol) and NaBr (sodium bromide).
The molecular equation is NaBr (s) + Ca(NO3)2 (aq) -> CaBr2 (s) + 2 NaNO3 (aq). The ionic equation is 2Na+ (aq) + 2NO3- (aq) + Ca2+ (aq) + 2Br- (aq) -> CaBr2 (s) + 2Na+ (aq) + 2NO3- (aq).
The balanced equation for the formation of sodium bromide from sodium and bromine is: 2 Na + Br2 → 2 NaBr
2 Na + Br2 --> 2 NaBr
Any reaction occur between these compounds. For preparation:NaOH + HBr = NaBr + H2OKOH + HNO3 = KNO3 + H2OCaCl2 + H2S + CaS + 2 HCl
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
The balanced equation for sodium bromide (NaBr) and silver nitrate (AgNO3) is: 2NaBr + AgNO3 → 2NaNO3 + AgBr.
The reaction between sodium bromide (NaBr) and silver nitrate (AgNO3) results in the formation of silver bromide (AgBr) and sodium nitrate (NaNO3). The balanced chemical equation for this reaction is: 2NaBr + AgNO3 → 2AgBr + 2NaNO3
Nickel chloride
The hydrolysis reaction of C4H9Br with NaOH can be represented as follows: C4H9Br + NaOH -> C4H9OH + NaBr This reaction involves the substitution of the bromine atom in C4H9Br with the hydroxide ion from NaOH, resulting in the formation of C4H9OH (butanol) and NaBr (sodium bromide).
Sodium bromide (NaBr) has a weight of 102.89 grams per mole. Determining the mass of NaBr in a mixture can be calculated if the constituent weights of all the others are known. The total masses of the knows can be subtracted by the overall weight to isolate the mass of NaBr.
Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] First check that the given equation is balanced ... it isn't ... so the first thing to do is balance the equation: balancing Na: 2Na2S2O3 + AgBr → NaBr + Na3[Ag(S2O3)2] and everything is now balanced so we've got the balanced equation molar mass AgBr = 107.87 + 79.90 = 187.77 g/mol mol AgBr available = 42.7 g AgBr x [1 mol / 187.77 g] = 0.2274 mol AgBr from the balanced equation the mole ratio AgBr : Na2S2O3 = 1 : 2 so mol Na2S2O3 required = 0.2274 mol AgBr x [ 2 mol Na2S2O3 / mol AgBr] = 0.455 mol Na2S2O3 (to 3 sig figs)
Sodium bromide dissassociates into Na+ and Br- ions when it is dissolved in water.NaBr + H2O = Na+ and Br- aq.