The reaction between H3PO4 (phosphoric acid) and NaOH (sodium hydroxide) can be represented by the following equation: H3PO4 + 3NaOH → Na3PO4 + 3H2O. Here, one molecule of phosphoric acid reacts with three molecules of sodium hydroxide to produce one molecule of sodium phosphate and three molecules of water.
Mixing hydrochloric acid (HCI) with sodium hydroxide (NaOH) in water (H2O) will result in a neutralization reaction, producing sodium chloride (NaCl) and water. The balanced chemical equation for this reaction is: HCl + NaOH → NaCl + H2O.
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The reactants in the reaction are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The chemical reaction is:H3PO4 + 3 NaOH + Na3PO4 + 3 H2O
The reaction between H3PO4 (phosphoric acid) and NaOH (sodium hydroxide) can be represented by the following equation: H3PO4 + 3NaOH → Na3PO4 + 3H2O. Here, one molecule of phosphoric acid reacts with three molecules of sodium hydroxide to produce one molecule of sodium phosphate and three molecules of water.
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
Yes, mixing sodium phosphate (Na3PO4) and cobalt(II) chloride (CoCl2) will lead to a precipitation reaction. Cobalt(II) phosphate (Co3(PO4)2), which is insoluble in water, will form as a precipitate. The reaction occurs when the phosphate ions from Na3PO4 react with cobalt ions from CoCl2, resulting in the formation of the solid precipitate.
Mixing hydrochloric acid (HCI) with sodium hydroxide (NaOH) in water (H2O) will result in a neutralization reaction, producing sodium chloride (NaCl) and water. The balanced chemical equation for this reaction is: HCl + NaOH → NaCl + H2O.
The compound formed by Na+ and PO43- ions is sodium phosphate, which has the chemical formula Na3PO4.
Na3PO4 and CuSO4
The reactants are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
3, 2, 2, 1
2 Mg + 2 NaOH-------2 MgO + H2 + 2 Na 2 Al + 6 NaOH------2 Na3AlO3 + 3 H2
The reactants in the reaction are hydrochloric acid (HCl) and sodium hydroxide (NaOH).
The molarity of Na+ ions in a 0.25 M solution of Na3PO4 is 0.75 M. This is because each formula unit of Na3PO4 dissociates into 3 Na+ ions in solution. Therefore, the concentration of Na+ ions is three times the molarity of the Na3PO4 solution.