Na, Rb, Al3+, and S2- do not have a noble gas configuration as they do not have the complete outer shell of electrons like a noble gas. O2, Br, Ca, and O2- have noble gas configurations as they either have a complete outer shell of electrons or have gained/lost electrons to achieve a stable noble gas configuration.
The pseudo noble-gas electron configuration has the outer three orbitals filled, the s, p and d- s2p6d10 (18 electrons total) and so is fairly stable. Elements that attain this electron configuration are at the right side of the transition metals (d-block). Br-, I-, Se2-
A bromine atom (Br) needs to gain one electron to achieve a full outer shell of electrons like a noble gas. This would give it the electron configuration of the noble gas krypton (Kr).
Br-, like the other halogens F-, Cl-, Br-, I-. They would obtain one electron to have noble gas electron configuration. Therefore, one negative charge.
Both Li and K lose electrons to get noble gas configuration. Br gains an electron to get noble gas configuration. So K is more likely to form a compound with Br.Potassium is a metal in group 1. It usually forms ionic compounds with other non metallic elements. From these elements, it is more likely to bond with bromine. Recall that lithium is as in the same family as potassium.
The symbol for the most stable ion of bromine is Br-, which is the bromide ion. Bromine typically forms anions by gaining one electron to achieve a stable electron configuration similar to a noble gas.
The noble gas shortcut for Br (Bromine) is [Ar] 4s2 3d10 4p5. The noble gas Argon (Ar) has an electron configuration of 1s2 2s2 2p6 3s2 3p6, which is the closest noble gas with a lower atomic number to Bromine.
The electron configuration of bromine is: [Ar]4s23d104p5.
The noble gas configuration for bromine's ion (Br-) is [Kr] 4d10 5s2 5p6, which is equivalent to the electron arrangement of krypton. Bromine gains an electron to achieve a stable octet configuration like a noble gas.
To achieve noble gas configuration, Bromine must gain one electron. In doing so, it obtains the electron configuration of Krypton. It's new complete electron configuration would be: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6.
The pseudo noble-gas electron configuration has the outer three orbitals filled, the s, p and d- s2p6d10 (18 electrons total) and so is fairly stable. Elements that attain this electron configuration are at the right side of the transition metals (d-block). Br-, I-, Se2-
A bromine atom (Br) needs to gain one electron to achieve a full outer shell of electrons like a noble gas. This would give it the electron configuration of the noble gas krypton (Kr).
The element with the noble gas configuration Ar 4s2 3d10 4p5 is bromine (Br), which has an atomic number of 35. It is in the halogen group and has seven valence electrons, making it reactive.
To achieve noble gas configuration, Bromine must gain one electron. In doing so, it obtains the electron configuration of Krypton. Its new complete electron configuration would be: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6.http://wiki.answers.com/How_many_electrons_does_BR_need_to_achieve_noble_gas#ixzz19YDVJEtp
Actually all the ions will have. Al3+, O2- and N3- ions will have the same number of electrons as neon (10 electrons), whereas Br- ion will have the same number of electrons as krypton (36 electrons)
Br-, like the other halogens F-, Cl-, Br-, I-. They would obtain one electron to have noble gas electron configuration. Therefore, one negative charge.
The bromide ion, which has a charge of 1-, has one more electron than a neutral bromine atom. Its electron configuration is isoelectric with the noble gas krypton, so it has 36 electrons. Its electron configuration is [Ar]3d10 4s2 4p6. I apologize that the superscripts are not working. I put a space between the different sublevels to make it easier to understand.
K+ and argon have the same electron configuration