As a liquid, it weighs 12.2 pounds per gallon.
Thiosulfate can be standardised by adding excess potassium iodide solution to a known volume of a standard acidified solution of potassium dichromate, and then titrating the liberated iodine against the sodium thiosulfate solution.http://www.meduniv.lviv.ua/files/kafedry/tokshim/English/Analytical/Manuals_Analytchem/Iodometry.pdf
K2PbO2
The name of the ionic compound k2s is= Potassium Sulfide
One way is to react hot aqeous solution of potassium hydroxide (KOH) with sulphur (S). The products will be K2S3, K2S2O3 (potassium thiosulphate) and H2O. Answer by aditya rajesh, 8th student at millennium school in dubai.
The only known and possible reaction is the following redox (reduction-oxidation) reaction between I3- (Iodine-Iodide complex) and S2O32- (thiosulfate)I3- + 2 S2O32- --> 3 I- + S4O62-ox. + red.So the reaction between potassium iodide (KI) and potassium thiosulfate (K2S2O3) is NOT possible because they both are reductors (electron donors).Iodine-Iodide complex is essentially Iodine is an oxidator, bound to a non-reacting I- ion (Iodide)
K2s2o3
The chemical formula is K2S2O3
Thiosulfate can be standardised by adding excess potassium iodide solution to a known volume of a standard acidified solution of potassium dichromate, and then titrating the liberated iodine against the sodium thiosulfate solution.http://www.meduniv.lviv.ua/files/kafedry/tokshim/English/Analytical/Manuals_Analytchem/Iodometry.pdf
K2PbO2
Standardization of sodium thiosulfate uses potassium iodate with excess potassium iodide and acidified. Iodine is liberated and that is titrated with sodium thiosulfate. KIO3 + 5KI + 3H2SO4 -----> 3K2SO4 + 3H2O + 3 I2 I2 + 2Na2S2O3 -------> 2NaI + Na2S4O6 So 1 mole of KIO3 produces 3 moles of Iodine. 1 moles of iodine reacts with 2 moles of thiosulfate. So 6 moles of sodium thiosulfate react with 1 mole of potassium iodate KIO3.
The name of the ionic compound k2s is= Potassium Sulfide
One way is to react hot aqeous solution of potassium hydroxide (KOH) with sulphur (S). The products will be K2S3, K2S2O3 (potassium thiosulphate) and H2O. Answer by aditya rajesh, 8th student at millennium school in dubai.
The only known and possible reaction is the following redox (reduction-oxidation) reaction between I3- (Iodine-Iodide complex) and S2O32- (thiosulfate)I3- + 2 S2O32- --> 3 I- + S4O62-ox. + red.So the reaction between potassium iodide (KI) and potassium thiosulfate (K2S2O3) is NOT possible because they both are reductors (electron donors).Iodine-Iodide complex is essentially Iodine is an oxidator, bound to a non-reacting I- ion (Iodide)
Iodometric titration means the titration of triiodide. Preparation of triiodide can be prepared by adding solid iodine to excess potassium iodide, however since iodine sublimes it is more difficult to weigh than potassium iodate. The triiodide would then need to be standardized with primary standard grade arsenious oxide. A better way is to weigh potassium iodate and add to a small excess of potassium iodide. The two ions (iodide and iodate) will also form the needed triiodide in an acidic environment. If the reagent is made fresh this way it can be used to standardize thiosulfate. Iodide iodate of known normality can also be used to titrate unknown concentrations of sulfite. For example, steam boiler treatment applications.
Silver(I) thiosulfate = Ag2S2O3
The molar mass of potassium nitrate is 101,1032 g.
The formula for a thiosulfate ion is S2O3-2.