Standardization of sodium thiosulfate uses potassium iodate with excess potassium iodide and acidified. Iodine is liberated and that is titrated with sodium thiosulfate.
KIO3 + 5KI + 3H2SO4 -----> 3K2SO4 + 3H2O + 3 I2
I2 + 2Na2S2O3 -------> 2NaI + Na2S4O6
So 1 mole of KIO3 produces 3 moles of Iodine. 1 moles of iodine reacts with 2 moles of thiosulfate. So 6 moles of sodium thiosulfate react with 1 mole of potassium iodate KIO3.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
The nunber of moles of oxygen is 2,5.
The answer is 3 moles of Cu)NO3)2..
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
The answer is 3 moles of Cu)NO3)2..
The nunber of moles of oxygen is 2,5.
1.2 Moles
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.