it has 6C 12H 6O what is it
There are 7 neutrons in a neutral 13 6C atom. This is determined by subtracting the atomic number (6) from the mass number (13).
The balanced decomposition chemical equation for hexane (C6H14) is: 2C6H14 → 6C + 7H2
You will need to specify the mass of C6H6 in order to calculate a number of moles. If you know the mass, the general formula is:n=m/M, where n is the number of moles, m the mass of C6H6 and M the molar mass (78.11g/moles)
When chemists name compounds, we look at the length of the parent chain (in this case, 6 carbons.) and the functional group(s) (in this case, carboxylic acid). A regular 6C (all single bonds) hydrocarbon is termed "hexane" , the prefix "hex-" denoting the 6 carbons. When naming a compound with the carboxylic acid functional group, we add the suffix "-oic acid". Thus, a 6C carboxylic acid is hexanoic acid
3-Hexene: CH3CH2CH=CHCH2CH3 to name alkenes: -identify the parent chain (how many carbon atoms are in formula=prefix) there are 6 carbon atoms so the prefix is "hex" (prefixes are online) then add the end of the word alkene --> "ene" to that prefix. -Label where the double bond is located (on which carbon atom that has the lowest numeral positioning, numbering from either side) 3-hexene, you know that the double bond is at the 3rd carbon atom -the hydrogen atoms are determined by the number of covalent bonds the carbon atom can have (4) the first "C" has 3 hydrogen atoms bonded to it because it's only using one bond the second "C" has only 2 because its bonding in front and behind it (using 2) the third "C" has 1, the double bond takes 2 and the bond behind uses 1 (3) hope this helps -Autumn
There are five carbon atoms in adenine.Its molecular formula is C5H5N5.For structural formulae, see the link below.
6c-4c =2c
It has not yet been determined if or when there will be an iPhone 6C.
q=6C V=3V U=qV=(6C)(3V)=18 J U(potential energy)=18 Joules (18J)
C2+6c-9
If: -110 = -4c-6c Then: c = 11
6c = 18 Therefore, c = 18/6 c = 3
LCM(2b, 6c) = 6bc.
(5a - 4b) + (2c - 3b - 6c) + a =5a - 4b + 2c - 3b - 6c + a =(5a + a) + (-4b - 3b) + (2c - 6c) =[ 6a - 7b - 4c ].
Glucose
a=2b 4b=6c becomes 2b=3c a=3c
6c - 4 = 12Add 4 to each side of the equation:6c = 16Divide each side by 6:c = 16/6 = 22/3