boron
electros removed from 2p orbitals
more shielded from the + nucleus so easily lost
krypton because it is an inert/noble gas, which means it has a complete outer shell and takes a lot of energy to remove an electron.
Ar P Al Na K In general the ionisation energy (this answer refers to first ionisation energy, although most of the principles mentioned here apply to all ionisation energies) increases as one moves across the period, this is due to an increasing nuclear charge and decreasing atomic radius (recall that F=(kq1q2)/r2 ). However there are exceptions to this, notably, on moving from group II to group III we see that ionisation energy decreases, like wise on moving from group V to group VI. The first of these decreases is a result of the additional electron occupying the p orbital (and therefore experiencing a lesser effective nuclear charge). The second decrease (which is less marked) is due to the additional electron being "placed" into an orbital already occupied by another electron (an electron pair is formed), these electrons have the same charge and therefore repel each other, as they are in the same orbital the repulsion is particularly strong, therefore the effective nuclear charge is less and first ionisation energy is lower. I hope this answer is acceptable, for more information see the Wikipedia article on electronic configuration.
Ionization energy generally increases across a period from left to right on the periodic table. This trend occurs because as you move across a period, the number of protons in the nucleus increases, resulting in a greater nuclear charge. This stronger attraction between the nucleus and the outer electrons requires more energy to remove an electron, thus increasing the ionization energy.
Element 115 on most modern periodic charts.
Na(g) --> Na+(g) + e- First ionisation energy is always: X(g) --> X+(g) + e- with X being an element
ionisation energy order for gr 14 is c>si>ge>sn<pb
Ionisation energy differs between elements due to variations in the number of protons in their nucleus, which affects the strength of the attraction between the electrons and the nucleus. Elements with higher atomic numbers typically have higher ionisation energies due to increased nuclear charge. Additionally, ionisation energy generally increases across a period and decreases down a group on the periodic table.
The ionisation energy increases across a period. Across a period, nuclear charge increases. The tendency to loose electron decreases.
Ionisation potential and ionisation energy are essentially the same concept - they both refer to the amount of energy required to remove an electron from an atom or molecule. The terms are often used interchangeably in practice.
ionisation energy order for gr 14 is c>si>ge>sn<pb
Ionisation energy decreases down the group. It is easy to remove an electron.
The first ionization energy of an atom or molecule describes the amount of energy required to remove an electron from the atom or molecule in the gaseous state.
1.A small atomic/ionic radius 2.therefore less number of protons 3. more net nuclear attraction between the positively charged nucleus 4. higher energy is needed to break those bonds. 5. therefore an element has high ionisation energy
the first ionisation energy is the energy required to remove the first most loosely bound elecctron from a neutral gaseous atom in its ground state.
when we go from left to right
Because, as we know that when we go across the period of the periodic table, the number of shells remain the same but the number of electrons and protons increases. So, Rb having its atomic number as 37 and Sr as 38, Strontium has got more nuclear charge as well as more electrons. As a result the first ionisation energy required to remove one electron is more in Strontium than Rubidium.
Ionisation energy, or alternatively quantum energy.