All of the Group 2 elements, the Alkaline earth metals, want to lose two electrons and form an ion with a +2 charge. And of these elements, it is radium that is the most reactive. Radium wants to lose its two valence electrons more than any of the other elements of its group.
Remember that reactivity increases as we move down the groups on the left side of the Periodic Table (with one exception). These elements each wish to shed their valence electron(s) and form an ion. In the case of the elements in Group 1 of the table, the Alkali metals, they wish to shed their single valence electron to end up with a +1 charge. And caesium, which is the second-to-last element in that group moving down, is a bit more reactive than francium, which is below it. That's the lone exception to the rule.
When we consider the elements of Group 2, we find that radium is the most reactive, as we've already stated. It (radium) is at the bottom of the Group 2 elements.
The element that forms a 3+ ion with ten electrons is sodium (Na). Sodium has 11 protons and normally has 11 electrons, but when it loses 3 electrons to form a 3+ ion, it has a total of 10 electrons.
The third period element that forms a 3- ion is sulfur.
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
The element with an electron configuration of Xe 4f14 corresponds to the element Gadolinium (Gd) with atomic number 64. When it forms a 4+ ion, it loses its 4 outer shell electrons, ending up with a stable electron configuration.
When phosphorus forms an ion, it typically gains three electrons to achieve a stable electron configuration. This results in the formation of a phosphide ion with a 3- charge.
The element that forms a 3+ ion with ten electrons is sodium (Na). Sodium has 11 protons and normally has 11 electrons, but when it loses 3 electrons to form a 3+ ion, it has a total of 10 electrons.
The element with atomic number 13 is aluminum (Al). When aluminum loses three electrons, it forms an ion with a 3+ charge, written as Al3+. This ion contains 13 protons, as the number of protons in an element's nucleus is equal to its atomic number.
The ion is awesom
The third period element that forms a 3- ion is sulfur.
The element hydrogen forms an ion with the same charge as the ammonium ion, which is +1. When hydrogen loses an electron, it becomes a hydrogen ion with a +1 charge, just like the ammonium ion.
The element that forms a 2+ ion with the same electronic configuration as Ar is Calcium (Ca). When Calcium loses two electrons, it attains the same electronic configuration as argon by having a full outer shell of electrons.
The compound with the 2+ ion that is the smallest with a filled d subshell is zinc (Zn^2+), and the anion that forms from the smallest halogen is fluoride (F^-). Therefore, the compound you are looking for is zinc fluoride (ZnF2).
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
A 2+ ion of boron is not commonly found, as boron usually forms a 3+ ion. Strontium typically forms a 2+ ion by losing two electrons.
The element with an electron configuration of Xe 4f14 corresponds to the element Gadolinium (Gd) with atomic number 64. When it forms a 4+ ion, it loses its 4 outer shell electrons, ending up with a stable electron configuration.
Strontium.
The sulfate ion is SO42-. Elements in group 16 form anions with a charge of 2-, for example oxygen forms the oxide, O2- anion.