Calcium
Mg2+: [1s22s22p6]
the atomic no of calcium is 20 so to reach the nearest noble gas electronic configuration it loses 2 electrons and forms + 2 ion.
Europium is element number 63, one of the Lanthanoids. The "3 plus" indicates its valence number is +3.
Silver
The electronic configuration of Ti4+ is [Ar] 3d0. This means that Titanium has lost all its 4 s-electrons and 4 d-electrons, leaving it with a full d shell.
2
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
Mg2+: [1s22s22p6]
The element with an electron configuration of Xe 4f14 corresponds to the element Gadolinium (Gd) with atomic number 64. When it forms a 4+ ion, it loses its 4 outer shell electrons, ending up with a stable electron configuration.
1s2 2s2 2p6 3s2 3p6
If it has 11 electrons it must have 11 protons to balance the charge. So the element is Na. But you know it's going to be an isotope of Na since the number of protons and number of neutrons are different. To find out which isotope you have, you must get the mass number which is just the number of protons plus the number of neutrons (remember, they are the only ones that have mass) 11+12= 23 So you have Na-23
the atomic no of calcium is 20 so to reach the nearest noble gas electronic configuration it loses 2 electrons and forms + 2 ion.
The electronic configuration of tin is: [Kr]D10.5s2.5p2.The electronic configuration of chromium(2+) is correct.
Europium is element number 63, one of the Lanthanoids. The "3 plus" indicates its valence number is +3.
It is not [Ar] 4s2 In V 3+ the element Vanadium is giving away 3 of its electrons. 50.9 - 3 is 47.9, about the same as Titanium (Ti). So the answer would be [Ar] 4s^0 3d^2
[Xe] Normally the electronic configuration for Barium would be [Xe] 6s2, but since you want it for Ba2+, you're missing two electrons. You get rid of the 6s2 and get [Xe].
Silver