It is not [Ar] 4s2
In V 3+ the element Vanadium is giving away 3 of its electrons. 50.9 - 3 is 47.9, about the same as Titanium (Ti). So the answer would be [Ar] 4s^0 3d^2
The electron configuration for V3 is Ar 3d2.
The electron configuration of V3 is Ar 3d2.
The electron configuration of a V3 ion is Ar 3d2.
2
Mg2+: [1s22s22p6]
The ground-state electron configuration for the V3 ion is Ar 3d2.
1s2 2s2 2p6 3s2 3p6
The electron configuration of a vanadium atom in its ground state in the V3 oxidation state is Ar 3d2.
what is the electronic configuration of the atomC6
The electronic configuration of tin is: [Kr]D10.5s2.5p2.
The element that forms a 2+ ion with the same electronic configuration as Ar is Calcium (Ca). When Calcium loses two electrons, it attains the same electronic configuration as argon by having a full outer shell of electrons.
The electronic configuration of copper is Ar 3d10 4s1.