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It is not [Ar] 4s2
In V 3+ the element Vanadium is giving away 3 of its electrons. 50.9 - 3 is 47.9, about the same as Titanium (Ti). So the answer would be [Ar] 4s^0 3d^2
What else can I help you with?
What is the electron configuration for V3?
The electron configuration for V3 is Ar 3d2.
What is the electron configuration of V3?
The electron configuration of V3 is Ar 3d2.
What is the electron configuration of a V3 ion?
The electron configuration of a V3 ion is Ar 3d2.
The electronic configuration of Li plus?
2
What is the electronic configuration of mg2 plus?
Mg2+: [1s22s22p6]
What is the ground-state electron configuration for the V3 ion?
The ground-state electron configuration for the V3 ion is Ar 3d2.
What is electronic configuration of k plus?
1s2 2s2 2p6 3s2 3p6
What is the electron configuration of a vanadium atom in its ground state in the v3 oxidation state?
The electron configuration of a vanadium atom in its ground state in the V3 oxidation state is Ar 3d2.
What is the electronic configuration of the atom C6?
what is the electronic configuration of the atomC6
The element that forms a 2 plus ion with the same electronic configuration as Ar?
The element that forms a 2+ ion with the same electronic configuration as Ar is Calcium (Ca). When Calcium loses two electrons, it attains the same electronic configuration as argon by having a full outer shell of electrons.
What is tins electronic configuration?
The electronic configuration of tin is: [Kr]D10.5s2.5p2.
What is electronic configuration of Nb plus 4?
The electronic configuration of niobium (Nb) in its neutral state is ( [Kr] 4d^4 5s^1 ). When niobium loses four electrons to become Nb(^{4+}), the configuration changes to ( [Kr] 4d^4 ), as the 5s and three of the 4d electrons are removed. Thus, the electronic configuration for Nb(^{4+}) is ( [Kr] 4d^4 ).
