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The electronic configuration of niobium (Nb) in its neutral state is ( [Kr] 4d^4 5s^1 ). When niobium loses four electrons to become Nb(^{4+}), the configuration changes to ( [Kr] 4d^4 ), as the 5s and three of the 4d electrons are removed. Thus, the electronic configuration for Nb(^{4+}) is ( [Kr] 4d^4 ).

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