4
Ground state configuration is 5s^1 4^4
Niobium (Nb) Because three 4d electrons = 3d^3
5
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
I am pretty sure its Pd (Palladium)
zero - after the 4s orbitals are filled at Calcium, the 3d orbitals start to fill - not until Gallium do the 4p orbitals start to fill.
Niobium (Nb) Because three 4d electrons = 3d^3
27
10 electrons.
5 valence electrons
5
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
8
Half and fully filled orbitals are more stable that other configurations. Because of this, the d orbital will take an extra electron from the s orbital in order to make it more stable. The actual configuration would be 5s1 4d4.
I am pretty sure its Pd (Palladium)
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
zero - after the 4s orbitals are filled at Calcium, the 3d orbitals start to fill - not until Gallium do the 4p orbitals start to fill.
Niobium only seems to have one valence electron. Why it doesn't have two like the rest of the transition metals is beyond me.