5
6
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
Niobium (Nb) Because three 4d electrons = 3d^3
Mo^3+ = [Kr] 4d^3
I am pretty sure its Pd (Palladium)
there are 16 orbitals in a n=4 shell *since there are 2 electrons in each orbital, that makes 32 electrons total here
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
Niobium (Nb) Because three 4d electrons = 3d^3
27
10 electrons.
Pwet NG KABAYO TAE MO MABAHO
8
Mo^3+ = [Kr] 4d^3
Use the formula n2 = max. number of electrons in shell. 42 = 16. 16 electrons.
I am pretty sure its Pd (Palladium)
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons
there are 16 orbitals in a n=4 shell *since there are 2 electrons in each orbital, that makes 32 electrons total here
4 Ground state configuration is 5s^1 4^4