I am pretty sure its Pd (Palladium)
Niobium (Nb) Because three 4d electrons = 3d^3
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[Kr]4d6 ion has 42 electrons. As it is a 3+ ion, the parent atom would have 45 electrons. This would make it Rhodium Rh.
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
4 Ground state configuration is 5s^1 4^4
Niobium (Nb) Because three 4d electrons = 3d^3
since it is in period 5 it contains 4d and 3d levels which both hold 10 electrons each. so therefore I (53) has 20 d electrons
The valence electrons fill in 4d orbital The electron configuration of yttrium is [Kr]4d15s2.
Yes Zr (atomic number 40) is the first transitional element in period 5 ('4d-block' metals).
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27
10 electrons.
[Kr]4d6 ion has 42 electrons. As it is a 3+ ion, the parent atom would have 45 electrons. This would make it Rhodium Rh.
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
The element is Yttrium, with the symbol Y
8
If you are filling in the electrons it will be in the 4d orbital. If you are removing electrons the first to come out is in the 5s electrons since transition metals lose 's' electrons before 'd' electrons