Antimony (Sb) has an atomic number of 51, and its electron configuration is [Kr] 5s² 4d¹⁰ 5p³. In the Sb³⁺ oxidation state, it loses three electrons, typically from the 5p and 5s orbitals, resulting in the configuration [Kr] 4d¹⁰. Consequently, Sb³⁺ has no unpaired electrons, as all its electrons are paired in the filled 4d subshell.
The element with 10 4d electrons in period 5 is zirconium (Zr). Zirconium has the atomic number 40 and is located in Group 4 of the periodic table. It is a transition metal, and its electron configuration includes 4d electrons along with 5s electrons. In its neutral state, zirconium has a total of 40 electrons, with the electron configuration [Kr] 5s² 4d².
The element tungsten (W) has 6 valence electrons.
The element with 3 valence electrons in the 4d sublevel is Yttrium (Y), which has the atomic number 39. Yttrium is located in group 3 of the periodic table and is characterized by its electron configuration of [Kr] 4d^1 5s^2. In this configuration, the 4d sublevel contributes one valence electron, while the 5s contributes two, totaling three valence electrons.
The electronic configuration of niobium (Nb) in its neutral state is ( [Kr] 4d^4 5s^1 ). When niobium loses four electrons to become Nb(^{4+}), the configuration changes to ( [Kr] 4d^4 ), as the 5s and three of the 4d electrons are removed. Thus, the electronic configuration for Nb(^{4+}) is ( [Kr] 4d^4 ).
In iodine (I), the electron configuration is [Kr]5s²4d¹⁰5p⁵. This means that there are 10 electrons in the 4d orbital.
There are 10 electrons in the 4d subshell of the ground state of Xenon.
The element with three 4d electrons is ruthenium (Ru), which has an atomic number of 44. The 4d sublevel can hold a maximum of 10 electrons, so with only three electrons, ruthenium has a partially filled 4d orbital.
Molybdenum (Mo) has a configuration of [Kr] 5s^1 4d^5. Therefore, it has 5 4d electrons.
4 Ground state configuration is 5s^1 4^4
Antimony (Sb) has an atomic number of 51, and its electron configuration is [Kr] 5s² 4d¹⁰ 5p³. In the Sb³⁺ oxidation state, it loses three electrons, typically from the 5p and 5s orbitals, resulting in the configuration [Kr] 4d¹⁰. Consequently, Sb³⁺ has no unpaired electrons, as all its electrons are paired in the filled 4d subshell.
The element with ten 4d electrons in Period 5 is Palladium (Pd), which has an electron configuration of [Kr] 4d^10.
The element with 10 4d electrons in period 5 is zirconium (Zr). Zirconium has the atomic number 40 and is located in Group 4 of the periodic table. It is a transition metal, and its electron configuration includes 4d electrons along with 5s electrons. In its neutral state, zirconium has a total of 40 electrons, with the electron configuration [Kr] 5s² 4d².
In a neutral zinc atom, there are 2 electrons in the 4d orbital and 2 electrons in the 4s orbital. Therefore, there are no 5s electrons in a zinc atom.
zero - after the 4s orbitals are filled at Calcium, the 3d orbitals start to fill - not until Gallium do the 4p orbitals start to fill.
2s: 2 electrons 5p: 6 4f: 14 3d: 10 4d: 10
The 4d subshell in the ground state of atomic xenon contains 10 electrons.