Most reactive metals, Zinc, being most common in practice, sodium Potassium Calcium etc
Copper sulfate dissolves in water, it does not react.
Copper sulfur oxygen
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.
When CuSO4 reacts with KCN, cyanide ion (CN-) replaces sulfate ion (SO4^2-) to form copper cyanide (Cu(CN)2) and potassium sulfate (K2SO4).
Copper sulfate dissolves in water, it does not react.
The solution of CuSO4 is blue.The solution of FeSO4 is green.
Copper sulfur oxygen
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.
Copper(II) sulfate (CuSO4) in aqueous solution typically appears as a blue-colored solution.
When CuSO4 reacts with KCN, cyanide ion (CN-) replaces sulfate ion (SO4^2-) to form copper cyanide (Cu(CN)2) and potassium sulfate (K2SO4).
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
CuSO4 isn't an element.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
One common method to separate hydrated CuSO4 from its aqueous solution is through the process of evaporation. By heating the solution, water evaporates leaving behind solid CuSO4. The solid can then be filtered to separate it from the remaining liquid.
The Iron rod(Fe) reacts with the Copper Sulphate. Substitution reaction takes place. Fe+CuSO4--> FeSO4 + Cu